Answer:
a. Which number is greater? 1/4 or 5/4 -3/4 or 5/8:
<u>answer</u><u>:</u><u> </u><u>5</u><u>/</u><u>4</u>
b. Which number is farther from 0? 1/4 or 5/4 -3/4 or 5/8:
<u>answer</u><u>:</u><u> </u><u>5</u><u>/</u><u>4</u>
c. Is the number that is farther from 0 always the greater number?:
<u>answer</u><u>:</u><u> </u><u>nah</u><u> </u><u>really</u><u>.</u>
A number can be further from zero but when it's a negative or positive. But negative value is less than zero.

There are several information's already given in the question. based on those information's, the answer can be easily deduced.
a. It is already given that 1% are defective. It is required to find the number that is needed to be checked to get 5 defective products.
Then
1% of X = 5
0.01X = 5
x = 5/0.01
= 500
b. <span>σ = square root [(<span><span><span><span>n^2</span>−1)/</span>12]
= square root [(250000 - 1)/12]
= square root [249999/12]
= square root (20833.25)
= 144.34
= 144
I hope the procedure is clear enough for you to understand. I also hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span></span></span>
Answer: 385
Step-by-step explanation:
Mean the three groups of 10 kids=35
Total weight of 3 groups (10x35)=350
Mean weight of 3 groups and one boy ( 35 + 350)=385
We either need to see a picture of this and/or get more information about the measurements of the triangle. In general, the area outside of the triangle will be the area of the semi-circle minus the area of the triangle itself, or: 1/2*49*3.14 - 1/2 b*h of the triangle. That first part, which is the area of the semi-circle, works out to 76.93 So based on the info we have, it becomes 76.93 - 1/2*b*h of the triangle = area outside of triangle.
In the balanced reaction
2 Fe + O₂ → 2 FeO
2 moles of iron (Fe) react with 1 mole of molecular oxygen (O₂) to produce 2 moles of iron oxide (FeO). The ratio of Fe to FeO is 1-to-1, so if one starts with 42.4 mol of Fe, one will end up with the same amount of FeO, 42.4 mol.
Look up the molar mass of Fe and O:
• Fe = 55.845 g/mol
• O = 15.999 g/mol
Then the molar mass of FeO is approximately 71.835 g/mol, and so the mass of 42.4 mol of FeO is
(42.4 mol) × (71.835 g/mol) ≈ 3050 g