Answer:
where ever your at looks dark.
Step-by-step explanation:
Answer:
See explaination
Step-by-step explanation:
Refer to attached file for table used in solving mean.
The mean of range is
\bar{R}=\frac{13.3}{20}=0.665
The mean of all six means:
\bar{\bar{x}}=\frac{1907.96}{20}=95.398
(a)
Here sungroup size is 5:
Range chart:
From constant table we have
D_{4}=2.114
So upper control limit:
UCL_{R}=D_{4}\cdot \bar{R}=2.114\cdot 0.665=1.40581
Lower control limit:
LCL_{R}=0.0000
Central limit: \bar{R}=0.665
Since all the range points are with in control limits so this chart shows that process is under control.
-----------------------------
X-bar chart:
From constant table we have
A_{2}=0.577
So upper control limit:
UCL_{\bar{x}}=\bar{\bar{x}}+A_{2}\cdot \bar{R}=95.398+0.577\cdot 0.665=95.78
Lower control limit:
LCL_{\bar{x}}=\bar{\bar{x}}-A_{2}\cdot \bar{R}=95.398-0.577\cdot 0.665=95.01
Central limit: \bar{\bar{x}}=95.398
Sample number 94.82 is not in teh limits of x-bar chart so it seems that process is not in control
Answer:
4Q a). angle1=55°
angle2=23°
angle3=63°
angle4=125°
5Q. x=35°
6Q. y=15°
8Q. C. 28°
9Q. Yes, they are congruent by S.S.S. congruence
10Q. A.A.S.
11Q. S.S.S.
12Q. Not possible
13Q. S.A.S.
14Q. S.S.S.
15Q. 66°
16Q. 24°
I hope it will be useful.
Step-by-step explanation:
7Q. angle1=angle3 (Alternate Interior Angles)
angle2=angle4 (A.I.A.)
angleXWZ=angleXYZ (opposite angles of a parallelogram)
By A.A.A. congruence criteria, they are congruent.
8Q. Hint: Make the diagram first!
AngleC is halved since M is the mid-point.
angleA=angleB (Property of an isosceles triangle)
which implies, angleAMC=angleBMC=90°
Thus, CM is perpendicular to AB.
I hope it will be useful.
For a line with slope m that passes through a point

, the point-slope form equation is the following.

We have a given slope of 4 and a given point of (7,5). Now, plug in the values.

That is the
point-slope form of the line. Now, let's change this into slope-intercept form. Slope-intercept form looks like the following:

Where m is the slope and b is the y-intercept. Let's do some algebra on our point-slop form equation to change it into slope-intercept form.

This was our equation. Let's use the distributive property on 4(x-7).

Now, add 5 to both sides of the equation

This the
slope-intercept form of the line. Thus, we have solved for both the point-slope form and the slope-intercept form. Hope this helps! :)
<h2>
Answer:</h2><h3>
Last option</h3>
![\textbf{$\left[\begin{array}{cc}x & y\\-3 & 12\\-6 & 24\\-9 & 36\end{array}\right]$}](https://tex.z-dn.net/?f=%5Ctextbf%7B%24%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%20%26%20y%5C%5C-3%20%26%2012%5C%5C-6%20%26%2024%5C%5C-9%20%26%2036%5Cend%7Barray%7D%5Cright%5D%24%7D)
<h2>
Step-by-step explanation:</h2>
Two variables have a proportional relationship if the ratios are equivalent. In other words, in this type of cases two quantities vary directly with each other, so we can write this in a mathematical language as follows:

Here
is the slope of the linear equation defined above. So, verifying that k is constant we have:

One way to prove this is by writing the equation that represents the table. From the two-point intercept form of the equation of a line we have:

So, this implies that the ordered pairs of the last option represent a proportional relationship