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BARSIC [14]
3 years ago
12

XYZ Oil Company has consistently lost $8 million each year for the past 7 years. Express the total loss as an integer.

Mathematics
2 answers:
QveST [7]3 years ago
7 0

Answer:It's D for sure


Step-by-step explanation:


NikAS [45]3 years ago
6 0
$56 million is the total for 7 years
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Can someone help me ?
Darina [25.2K]

Answer:

where ever your at looks dark.

Step-by-step explanation:

4 0
3 years ago
The following are quality control data for a manufacturing process at Kensport Chemical Company. The data show the temperature i
beks73 [17]

Answer:

See explaination

Step-by-step explanation:

Refer to attached file for table used in solving mean.

The mean of range is

\bar{R}=\frac{13.3}{20}=0.665

The mean of all six means:

\bar{\bar{x}}=\frac{1907.96}{20}=95.398

(a)

Here sungroup size is 5:

Range chart:

From constant table we have

D_{4}=2.114

So upper control limit:

UCL_{R}=D_{4}\cdot \bar{R}=2.114\cdot 0.665=1.40581

Lower control limit:

LCL_{R}=0.0000

Central limit: \bar{R}=0.665

Since all the range points are with in control limits so this chart shows that process is under control.

-----------------------------

X-bar chart:

From constant table we have

A_{2}=0.577

So upper control limit:

UCL_{\bar{x}}=\bar{\bar{x}}+A_{2}\cdot \bar{R}=95.398+0.577\cdot 0.665=95.78

Lower control limit:

LCL_{\bar{x}}=\bar{\bar{x}}-A_{2}\cdot \bar{R}=95.398-0.577\cdot 0.665=95.01

Central limit: \bar{\bar{x}}=95.398

Sample number 94.82 is not in teh limits of x-bar chart so it seems that process is not in control

4 0
3 years ago
SOMEONE PLS HELP ME ON ALL THESE ASAP!!!!!​
natulia [17]

Answer:

4Q a). angle1=55°

angle2=23°

angle3=63°

angle4=125°

5Q. x=35°

6Q. y=15°

8Q. C. 28°

9Q. Yes, they are congruent by S.S.S. congruence

10Q. A.A.S.

11Q. S.S.S.

12Q. Not possible

13Q. S.A.S.

14Q. S.S.S.

15Q. 66°

16Q. 24°

I hope it will be useful.

Step-by-step explanation:

7Q. angle1=angle3 (Alternate Interior Angles)

angle2=angle4 (A.I.A.)

angleXWZ=angleXYZ (opposite angles of a parallelogram)

By A.A.A. congruence criteria, they are congruent.

8Q. Hint: Make the diagram first!

AngleC is halved since M is the mid-point.

angleA=angleB (Property of an isosceles triangle)

which implies, angleAMC=angleBMC=90°

Thus, CM is perpendicular to AB.

I hope it will be useful.

7 0
3 years ago
Write the point-slope form, then use that to write the slope-intercept form of the equation
Mashcka [7]
For a line with slope m that passes through a point (x_1, y_1), the point-slope form equation is the following.

y-y_1=m(x-x_1)

We have a given slope of 4 and a given point of (7,5). Now, plug in the values.

\boxed{y-5=4(x-7)}

That is the point-slope form of the line. Now, let's change this into slope-intercept form. Slope-intercept form looks like the following:

y=mx+b

Where m is the slope and b is the y-intercept. Let's do some algebra on our point-slop form equation to change it into slope-intercept form.

y-5=4(x-7)

This was our equation. Let's use the distributive property on 4(x-7).

y-5=4x-28

Now, add 5 to both sides of the equation

\boxed{y=4x-23}

This the slope-intercept form of the line. Thus, we have solved for both the point-slope form and the slope-intercept form. Hope this helps! :)
7 0
3 years ago
Which table of ordered pairs represents a proportional relationship
GalinKa [24]
<h2>Answer:</h2><h3>Last option</h3>

\textbf{$\left[\begin{array}{cc}x & y\\-3 & 12\\-6 & 24\\-9 & 36\end{array}\right]$}

<h2>Step-by-step explanation:</h2>

Two variables have a proportional relationship if the ratios are equivalent. In other words, in this type of cases two quantities vary directly with each other, so we can write this in a mathematical language as follows:

y=kx

Here k is the slope of the linear equation defined above. So, verifying that k is constant we have:

k=\frac{24-12}{-6-(-3))}=\frac{36-24}{-9-(-6)}=\frac{36-12}{-9-(-3)}=-4 \\ \\ \therefore \boxed{k=-4}

One way to prove this is by writing the equation that represents the table. From the two-point intercept form of the equation of a line we have:

y-y_{1}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1}) \\ \\ P(x_{1},y_{1})=P(-3,12) \\ \\ P(x_{2},y_{2})=P(-6,24) \\ \\ Subtituting \ x_{1}, x_{2}, y_{1}, y_{2}: \\ \\ y-12=\frac{24-12}{-6-(-3)}(x-(-3)) \\ \\ y-12=-4(x+3) \\ \\ Solving: \\ \\ y-12=-4x-12 \\ \\ Adding \ 12 \ to \ both \ sides: \\ \\ y-12+12=-4x-12+12 \\ \\ \boxed{y=-4x}

So, this implies that the ordered pairs of the last option represent a proportional relationship

5 0
3 years ago
Read 2 more answers
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