All categories

3 years ago

I. need help plsssssssssssssssss

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

3 0

Answer:

I believe it is 1 4 2

Step-by-step explanation:

You might be interested in

Scorpion4ik [409]

Answer:

x-intercept: (4, 0)

y-intercept: (0, 3)

Step-by-step explanation:

The intercepts of the equation can be found by setting each variable to zero and solving for the other. The graph will be a line through the intercept points.

<h3>Intercepts</h3>

Setting x=0 and solving for y, we have ...

4y -12 = 0 ⇒ y = 12/4 = 3

Setting y=0 and solving for x, we have ...

3x -12 = 0 ⇒ x = 12/3 = 4

The intercepts are ...

x-intercept: (4, 0)

y-intercept: (0, 3)

<h3>Graph</h3>

The line will go through these intercept points.

3 0

2 years ago

It is estimated that t-weeks into a semester, the average amount of sleep a college math student gets per day S(t) decreases at

goldenfox [79]

Answer:

s(15)= $\frac{-3}{2} e^{15^{2} } +9.6$

Step-by-step explanation:

Before to getting started ,we have to consider the function which represents sleep decline rate S'(t) = $-3te^{t^{2} } \\$

Since this function is interpreted in this case as a rate of change, we can deduce this funcion is the first derivative of the function of average amount of sleep (S(t)).

In order to find S(t), we will integrate S'(t)

$\int\limits^ {} -3t3e^{t^{2} } \, dx \\$

This case corresponds to intergration by substitution

Substituting u= $x^{2} \\$

Computting the differential of u

$\frac{du}{dt} =2tdt\\$

Now, let's go back to our integral and write it in terms of u, using both definition of u and its defferential.

$\int\limits^{}-3te^{u} \, \frac{1}{2t}du \\\\\int\limits^{}\frac{-3}{2} e^{u}du\\$

The integral of a exponential function is itself. So the result is:

$\frac{-3}{2} e^{u} +c$

Now substitute u back in:

$\frac{-3}{2} e^{t^{2} } +c$

This answer correspond to function of average amount of sleep.

We know that when the semester begins (t=0) , math students sleep an average of 8.1 hours per day so we will use this info in order to find the value of c.

$s(0)=\frac{-3}{2} e^{0^{2} } +c=8.1\\\\\frac{-3}{2} +c=8.1$