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Aleonysh [2.5K]
3 years ago
11

What Is 8÷856....Plz help

Mathematics
1 answer:
otez555 [7]3 years ago
4 0
0.00934579439 Now I'm just waiting until 20 charac- done
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What’s the median for 55, 42, 78, 99, 69, 83, 74, 83, 97
soldier1979 [14.2K]
The median of this is 78
8 0
2 years ago
Given: mMEJ=30°,<br> mMFJ= 50°<br> Find: mKL, mMJ
makvit [3.9K]

Applying the angles of intersecting secants theorem, the measures of the arcs are:

m(KL) = 20°; m(MJ) = 80°.

<h3>What is the Angles Intersecting Secants Theorem?</h3>

When two secants intersect and form an angle outside the circle, the measure of the angle formed is half the positive difference of the measures of the intercepted arcs.

Given the following:

  • m∠MEJ = 30°
  • m∠MFJ = 50°

m∠MEJ = 1/2(MJ - KL)

30 = 1/2(MJ - KL)

60 = MJ - KL

KL = MJ - 60

m∠MFJ = 1/2(MJ + KL)

50 = 1/2(MJ + MJ - 60)

100 = 2MJ - 60

2MJ = 100 + 60

2MJ = 160

MJ = 160/2

MJ = 80°

KL = MJ - 60 = 80 - 60

KL = 20°

Thus, applying the angles of intersecting secants theorem, the measures of the arcs are:

m(KL) = 20°; m(MJ) = 80°.

Learn more about angles of intersecting secants theorem on:

brainly.com/question/1626547

4 0
2 years ago
Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distribute
bulgar [2K]

Answer:

The area of the shaded region is 0.2898.

Step-by-step explanation:

Let <em>X</em> represent the IQ scores of adults.

It is provided that X\sim N(100,15^{2}).

Compute the probability of an adult having an IQ between 106 and 124 as follows:

P(106

                             =P(0.40

*Use a <em>z</em>-table.

Thus, the area of the shaded region is 0.2898.

4 0
3 years ago
Determine the equation of the circle graphed below.
sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and  ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

<u>Find the centre of the circle.</u>

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

      Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})

                 =(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)

<u>Find the radius of the circle.</u>

Radius = \frac{Diameter }{2}

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}

               =\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6

Therefore,

    Radius ,r = \frac{6}{2} = 3

<u>Standard equation of a circle:</u>

<u></u>(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.<u></u>

Therefore , equation of the circle ;

                    (x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9

6 0
3 years ago
On a coordinate grid, point P is at (2, 1) and point R is at (−6, −5). Points Q and S are a reflection of both points across the
netineya [11]
I think the answer is

Q (2,-1)
S (-6,5)
7 0
3 years ago
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