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34kurt
3 years ago
5

Your family plans to start a small business in your neighborhood.Your father borrows $10,000 from the bank at an annual interest

rate of 8% for 36 months. What is the amount of interest he will pay on his loan?
Mathematics
1 answer:
Temka [501]3 years ago
4 0

Answer:

10000*8%*3

=$2400 loan interest


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The coordinates of a triangle are P(1, 4), Q(3, 6), and R(5, 2). The triangle is reflected over a line and its image coordinates
natta225 [31]

Answer:

Option 4. x = 0

Step-by-step explanation:

we know that

The rule of the reflection of a point across the y-axis is equal to

(x,y) -----> (-x,y)

The rule for reflecting over the Y axis is to negate the value of the x-coordinate of each point, but leave the y-value the same

The coordinates of triangle PQR are

P(1, 4), Q(3, 6), and R(5, 2)

Applying the rule of the reflection across the y-axis we have

P(1, 4) -----> P'(-1, 4)

Q(3, 6) ----> Q'(-3, 6)

R(5, 2)----> R'(-5, 2)

The reflection line is the y-axis

Remember that the equation of the y-axis is x=0

therefore

The equation of the reflection line is x=0

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Answer:

22

Step-by-step explanation:

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2x = 44

x = 22

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Emma has $100 to spend at the pet store. She needs to buy 1 bag of dog food and 2 chew toys how many catnip toys can Emma buy
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A rope is swinging in such a way that the length of the arc traced by a knot at its bottom end is decreasing geometrically. If t
nikdorinn [45]

Answer:

<em>The length of the arc on the sixth swing was </em><em>12.18 ft.</em>

Step-by-step explanation:

A rope is swinging in such a way that the length of the arc traced by a knot at its bottom end is decreasing geometrically.

The third arc is 22 ft. long and the seventh arc is 10 ft.

Hence, the 3rd term is 22 and 7th term is 10.

The length of the arc on the sixth swing is asked, so we have to calculate the 6th term.

We know the nth term in GP is,

T_n=ar^{n-1}

So,

T_3=ar^{3-1}=ar^2  ----------------1

T_7=ar^{7-1}=ar^6  ----------------2

Dividing equation 2 by 1,

\Rightarrow \dfrac{T_7}{T_3}=\dfrac{ar^6}{ar^2}

\Rightarrow \dfrac{10}{22}=\dfrac{ar^6}{ar^2}

\Rightarrow \dfrac{10}{22}=\dfrac{r^6}{r^2}

\Rightarrow \dfrac{r^6}{r^2}=\dfrac{10}{22}

\Rightarrow r^4=\dfrac{10}{22}

\Rightarrow r=\sqrt[4]{\dfrac{10}{22}}

\Rightarrow r=0.8211

Then the 6th term will be,

T_6=ar^{6-1}=ar^5  ----------------3

Dividing equation 2 by 3,

\Rightarrow \dfrac{T_7}{T_6}=\dfrac{ar^6}{ar^5}

\Rightarrow \dfrac{10}{T_6}=\dfrac{a(0.8211)^6}{a(0.8211)^5}

\Rightarrow \dfrac{10}{T_6}=0.8211

\Rightarrow T_6=\dfrac{10}{0.8211}=12.18\ ft

Therefore, the length of the arc on the sixth swing was 12.18 ft.


6 0
3 years ago
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