How do you find sin 30 of a unit circle?
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Answer:
The sample data confirm the geneticist's prediction that 75% of the offspring from this cross will have red flowers.
Step-by-step explanation:
A Chi-square goodness of fit test can be used to test the claim made by the geneticist.
The hypothesis is defined as:
<em>H₀</em>: There is no difference between the observed and expected value,i.e. <em>p</em>₁ < 0.75.
<em>Hₐ</em>: There is a significant difference between the observed and expected value, i.e. <em>p</em>₁ > 0.75.
The test statistic is:
Consider the tables attached below.
The value of the test statistic is:
The critical value is:
*Use a Chi-square table.
The critical region is:
The test statistic value of 25.8133 lies in the critical region.
The null hypothesis is rejected at 1% level of significance.
<u>Conclusion</u>:
As the null hypothesis is rejected it can be concluded that 75% of the offspring from this cross will have red flowers.
