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kaheart [24]
2 years ago
5

A ball is thrown from an initial height of 3 feet with an initial upward velocity of 28 ft/s. The ball's height h (in feet) afte

r 1 seconds is given by the following:
h = 3 +28t-16t^2
Find all values of 1 for which the ball's height is 11 feet.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)
1 seconds
DO
х
?
initial
height
ground
Mathematics
1 answer:
dimaraw [331]2 years ago
7 0

The value of t  at a height of 11 feet is 0.36 sec when the ball is going upwards and 1.39 seconds when the ball is coming downwards.

<h3>What is a quadratic equation?</h3>

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers.

It is written in the form of ax²+bx+c.

Given that the height of the ball at time t is given by the function,

h(t) = 3+ 28t -16t^2

where t is in seconds and h is in feet.

Now, the height of the ball is given to be 11 feet, therefore, substituting the value of h in the function as 11,

h(t) = 3+ 28t -16t^2\\\\11 = 3+ 28t -16t^2\\\\-16t^2 + 28t +3 -11 = 0\\\\-16t^2 + 28t -8 = 0

Now, solving the given quadratic equation, we will get,

x= \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t = \dfrac{-(28)\pm \sqrt{(28)^2-4(-16)(-8)}}{2(-16)}\\\\t= 0.36\ or\ 1.39

Hence, the value of t  at a height of 11 feet is 0.36 sec when the ball is going upwards and 1.39 seconds when the ball is coming downwards.

Learn more about Quadratic Equations:

brainly.com/question/2263981

#SPJ1

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Is the ordered pair (0, 4) a solution of the inequality y≤x−3? Explain.
Andrew [12]

The ordered pair (0,4) does not satisfy the inequality thus, it will be not the solution to the given inequality.

<h3>What is inequality?</h3>

A mathematical phrase in which the sides are not equal is referred to as being unequal. In essence, a comparison of any two values reveals whether one is less than, larger than, or equal to the value on the opposite side of the equation.

As per the given inequality,

y ≤ x - 3

Put x = 0

y ≤ 0 - 3

y ≤ -3

Since 4 ≤ -3 is the wrong statement thus it will not satisfy the inequality.

Hence "The ordered pair (0,4) does not satisfy the inequality thus, it will be not the solution to the given inequality".

For more about inequality,

brainly.com/question/20383699

#SPJ1

4 0
1 year ago
Read 2 more answers
HELP ASAP PLEASE
Stels [109]
Solution (1) using angles of sectors:

Area of A = pi r^2  x 90/360 = 4.9

Area of B = pi r^2 x 270/360 = 14.2 


Check:  Area of A/B = 4.9/14.72 = 1/3 (as given)

Solution (2) using given info:

Area of B + Area of A = area of circle

Area of B + 1/3 Area of B =  3.14 * (2.5)^2 = 19.625

4/3 Area of B = 19.625

Area of B = 3/4 * 19.625

Area of B = 14.72

Area of A = 1/3 * 14.72 = 4.9

There is more solutions to this problem , like polar coordinate integration , and so on. for more just request. 



8 0
3 years ago
I will make you Brainliest
stepladder [879]

Answer and Step-by-step explanation:

Greetings!

I'm~Isabelle~Williams~and~will~be~answering~your~question!

For~the~first~question~the~answer~is~option~number~``4"

x\geq -1

For~the~second~question~the~answer~is~option~number~``4"~as~well.

x < 2

Hope~this~helps!~Have~an~amazing~day~ahead!

-Isabelle~Williams

6 0
3 years ago
Which expressions have the same value as .04 x .005. Select all that apply.
Novay_Z [31]

Answer:

Hello There!!

Step-by-step explanation:

0.04×0.005=0.0002

.0002 ✔

(4/100)=>0.04 × (5/1000)=>0.005=0.0002 ✔

(4 × .01)=>0.04 × (5 × .001)=>0.0005 =0.00002 ❌

.002 ❌

4 × 5 × .00001=0.0002 ✔

hope this helps,have a great day!!

~Pinky~

4 0
3 years ago
A boat travels 30 miles up the river in the same amount of time it takes to travel 38 miles down the same river. If the current
Ksenya-84 [330]
X miles per hour  -  <span> speed of the boat in still water
(x - 2)  -  speed up the river
(x + 2)  -  speed down the river
</span>
\frac{30}{x - 2} = \frac{38}{x + 2}
30 * (x + 2) = 38 * (x - 2)
30x + 60 = 38x - 76
- 8x = - 136
x = 17 miles per hour  -  <span>the speed of the boat in still water.</span>
5 0
2 years ago
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