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PtichkaEL [24]
3 years ago
12

Find p (-5) p(3) for p(x)=2x^5-9x^4-2x^2+12x-2

Mathematics
1 answer:
Margarita [4]3 years ago
8 0

Answer:

We have to evaluate the function p with the numbers on the argument of them, that is:

p(-5) = -11887

p(3)= -191

Step-by-step explanation:

First we are going to evaluate the functions and then to replace x by the corresponding number on the argument:

p(-5)= 2 (-5)^5 -9(-5)^4 -2(-5)^2+12(-5) +2 = -11887

p(3) =2(3)^5-9(3)^5-2(3)^2+12(3)-2 =-191

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Answer:

r = 2\sqrt{5}

(x - 3)^{2} + ( y - 2)^{2} = 20

Is this a live test question or a homework question?

Step-by-step explanation:

the radius is the distance between (3, 2) and (5, -2)

r^{2} = {(3 - 5)^{2} + (2 + 2)^{2}  }

    =  (-2)^{2} + 4^{2}

    =  4 + 16 = 20

r = \sqrt{20 } = 2\sqrt{5}

Equation of circle:   (x - 3)^{2} + ( y - 2)^{2} = 20

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Find the area of the region enclosed by the graphs of the functions
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Answer:

\displaystyle A = \frac{8}{21}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
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  4. Multiplication
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Equality Properties

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Area - Integrals

Integration Rule [Reverse Power Rule]:                                                                 \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                      \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Addition/Subtraction]:                                                          \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Area of a Region Formula:                                                                                     \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

*Note:

<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>

<u />

<u>Step 1: Define</u>

f(x) = x²

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Bounded (Partitioned) by x-axis

<u>Step 2: Identify Bounds of Integration</u>

<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

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Upper Bound: 1

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Topic: AP Calculus AB/BC (Calculus I/II)  

Unit: Area Under the Curve - Area of a Region (Integration)  

Book: College Calculus 10e

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