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2 years ago

Find p (-5) p(3) for p(x)=2x^5-9x^4-2x^2+12x-2

Mathematics

1 answer:

Margarita [4]2 years ago

8 0

Answer:

We have to evaluate the function p with the numbers on the argument of them, that is:

p(-5) = -11887

p(3)= -191

Step-by-step explanation:

First we are going to evaluate the functions and then to replace x by the corresponding number on the argument:

p(-5)= 2 (-5)^5 -9(-5)^4 -2(-5)^2+12(-5) +2 = -11887

p(3) =2(3)^5-9(3)^5-2(3)^2+12(3)-2 =-191

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Avery’s water bottle holds 300 milliliter. Dashawn’s container holds 3/4 as much water. How many milliliters do both containers

Nady [450]

Answer:

Both containers hold 225 ml.

Step-by-step explanation:

300/4 =75 so 1/4 is equal to 75 mL

300-75=225mL

Dashawn's water bottle holds 225mL

Hope this helps! :)

<h3>CloutAnswers</h3>

8 0

3 years ago

Read 2 more answers

A sociologist was investigating the ages of grandparents of high school students. From a random sample of 10 high school student

umka2103 [35]

Answer:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_{M}= 69.8$ represent the mean for the age of grandmother

$\bar X_{F}= 71.6$ represent the mean for the age of grandfather

$s_{M}= 8.38$ represent the sample deviation for the age of grandmother

$s_{F}= 6.65$ represent the sample deviation for the age of grandfather

$n_M = n_F= 10$

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_{M} -\bar X_F) \pm t_{\alpha/2} \sqrt{\frac{s^2_M}{n_M} +\frac{s^2_F}{n_F}}$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n_M +n_F-2=10+10-2=18$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,18)".And we see that $t_{\alpha/2}=2.101$

And replacing we got:

$(69.8-71.6) -2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= -8.908$

$(69.8-71.6) +2.101 \sqrt{\frac{8.38^2}{10} +\frac{6.65^2}{10}}= 5.308$

So then the confidence interval for the difference of means is given by:

$-8.908 \leq \mu_M -\mu_F \leq 5.308$

5 0

3 years ago

In the expression 2(10x) + 15y, x represents the number of hours Nina works in a week at a clothing store and y represents the n

ale4655 [162]

Answer:

The statement which is true in the choices is the third item in the choices such as "Nina makes 20x dollars at the clothing store each week". It was clearly stated in the given that x represent the total number of hours she worked in a week. This statement made the other items in the choices wrong.

Step-by-step explanation:

I hope this helps you :)

6 0

3 years ago

Read 2 more answers

12 divided by 5/6 (pretty easy but im lazy)<3

Mumz [18]

Answer:

14.4

Step-by-step explanation:

Hope this helps you :)

6 0