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Vitek1552 [10]
3 years ago
14

The length of a rectangular pool is 6 meters less than twice the width. If the pool's perimeter is 72 meters, what is the width?

Mathematics
1 answer:
Gnoma [55]3 years ago
5 0
Width is 14 meters

14 doubled is 28-6 is 22
22+22+14+14=72
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Select all that apply.
vfiekz [6]

Answer:

1/3 , 4/15 , 5/6

Step-by-step explanation:

All you have to do is plug the fractions in your calculator and you see that 1/3, 4/15, and 5/6 are repeating, but the others stop after only a couple of decimal places.

Hope this helps!

4 0
3 years ago
PLZ HELP What is the mode interval for the histogram? Science Test Scores Frequency No Бел о об - 1 50-59 60-69 70-79 80-89 90-1
Ksju [112]

Answer: You are correct. The mode is between 90 and 100

This is because the tallest bar corresponds to this interval. The mode is the most frequent value.

4 0
2 years ago
Read 2 more answers
Calculate the distance between each given pair of points. Round your answer to the nearest tenth, if necessary.
Ksju [112]
The answer is 5 

Here are the steps:

First off, we will be using the distance formula of 
d=\sqrt{(x_ {2}- x_{2}) ^{2}+( y_{2}- y_{1})^2     }

So we have the ordered pairs of (3,1) and (6,5)

Once you plug them into the formula it should look like this: 
d= \sqrt{(6-3)^2+(5-1)^2}

Now we do the math inside the parenthesis and end up with:
d=\sqrt{3^2+4^2}

Then you multiply by the power and simplify to get:
d=\sqrt{25}

And the \sqrt{25}=5

So your answer is 5
8 0
3 years ago
What's the answer to this question?​
Wewaii [24]

Answer: 10

Step-by-step explanation:

Use Pythagorean theorem!

a^2+b^2=c^2

6^2+8^2=c^2

64+36=c^2

100=c^2

Take the square root of 100 and you get c=10

5 0
3 years ago
Read 2 more answers
The rectangular coordinates of a point are given. Find the polar coordinates ​(r,theta​) of this point with theta expressed in r
alexandr402 [8]

Answer:}

In polar coordinates P is

P  ( 12 ; 2.618 )  

Step-by-step explanation:

The point (ectangular coordinates)  

P ( -6√3  ;   6 )       P  (  x ; y )

Polar coordinates   P ( r  ;  θ )

x = r cos θ

y = r sin θ                  r > 0    and     0  ≤ θ ≤ 2π

Then

r  =  √ (x)² + (y)²        r  =  √(36)²*3 +( 36)²       r = √144

r  =  12   (hypothenuse module always positive)

The point   P  ( -6√3  ;   6 )   is in second cuadrant  between 90° and 180°

angle between  r  and horizontal axis x  is equal to θ

tan α =  l.opp/ l.adj.    tan θ =  y/x       tan θ = - 6 /6√3

tan α = - 1/√3

Then α  =  180⁰ - 150⁰  = 30⁰  or     θ =  150⁰

to express that value in radians we have :

1 π radian      =   180⁰         ⇒   3,1416   radians  =  180⁰

                                                      x ??                  =   150⁰

x =  radians

Finally the point is   P  ( 12 ; 2.618 )  

6 0
3 years ago
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