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padilas [110]
3 years ago
13

Prove that 1+cosA/sinA + sinA/1+cosA=2cosecA

Mathematics
1 answer:
Alla [95]3 years ago
5 0
\frac{1+cos\alpha}{sin\alpha}+\frac{sin\alpha}{1+cos\alpha}=2cosec\alpha\\\\L=\frac{(1+cos\alpha)(1+cos\alpha)+sin\alpha\cdot sin\alpha}{sin\alpha(1+cos\alpha)}=\frac{1+2cos\alpha+cos^2\alpha+sin^2\alpha}{sin\alpha(1+cos\alpha)}\\\\=\frac{1+2cos\alpha+1}{sin\alpha(1+cos\alpha)}=\frac{2+2cos\alpha}{sin\alpha(1+cos\alpha)}=\frac{2(1+cos\alpha)}{sin\alpha(1+cos\alpha)}\\\\=\frac{2}{sin\alpha}=2\cdot\frac{1}{sin\alpha}=2cosec\alpha=R
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Answer:

Last choice.

Step-by-step explanation:

To find the option that is equivalent to this equation, we can begin by narrowing down our options. The slope contains a negative number, meaning the second point must have a lower y value than the first.

Using this criteria, we can eliminate the first and the third answer. Now, we can test the second and fourth answer.

We can test using the slope formula and plugging in values. When the slope formula: m= \frac{y_{2}-y_{1}  }{x_{2} -x_{1} }

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Choice 2:

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Choice 4:

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4 0
3 years ago
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Fiesta28 [93]
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Step-by-step explanation:

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