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svp [43]
3 years ago
14

You roll a die. What is the probability that 2 will not appear on the die

Mathematics
2 answers:
Bumek [7]3 years ago
6 0

Answer: 1/6 chance (In percentage is 16.6666666666667% chance)

Step-by-step explanation: There are 6 sides on a die

1 would appear = 1/6 chance

2 would appear = 1/6 chance

3 would appear = 1/6 chance

4 would appear = 1/6 chance

5 would appear =1/6 chance

6 would appear = 1/6 chance

(In percentage is 16.6666666666667% chance)

Shalnov [3]3 years ago
3 0

Answer: 5/6

Step-by-step explanation: its because it has a 5/6 chance to not land on 2 if i were to roll a die and ExPeCt to land on a 2 it would be 1/6

so the answer is "the probability is 5/6 chance"

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Answer:

x = 5

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Using this property means when you have something like the equation on the right side ( 4 ( x + 3 ) ) you multiply both the values in the parentheses by the number outside:

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Step 2: combine like terms

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This means that you need to get a variable one one side and a constant on the other:

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7 0
2 years ago
Read 2 more answers
Use the remainder theorem to determine the remainder when 3t2 + 5t − 7 is divided by t − 5. A. 93 B. 43 C. 107 D. 57
Usimov [2.4K]
Using remainder theorem, we get:

P(t) = 3t^{2} + 5t - 7

Substitute t = 5 into the equation:
P(5) = 3(5)^{2} + 5^{2} - 7
P(5) = 75 + 25 - 7 = 93

Thus, we get a remainder of 93 or (A)
7 0
3 years ago
Read 2 more answers
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