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3 years ago

You roll a die. What is the probability that 2 will not appear on the die

Mathematics

2 answers:

Bumek [7]3 years ago

6 0

Answer: 1/6 chance (In percentage is 16.6666666666667% chance)

Step-by-step explanation: There are 6 sides on a die

1 would appear = 1/6 chance

2 would appear = 1/6 chance

3 would appear = 1/6 chance

4 would appear = 1/6 chance

5 would appear =1/6 chance

6 would appear = 1/6 chance

(In percentage is 16.6666666666667% chance)

Shalnov [3]3 years ago

3 0

Answer: 5/6

Step-by-step explanation: its because it has a 5/6 chance to not land on 2 if i were to roll a die and ExPeCt to land on a 2 it would be 1/6

so the answer is "the probability is 5/6 chance"

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Heyyy can somebody answer this please ?

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Answer:

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3. Given the directed line segment AB, with endpoints A20, 6) and B(-16, 50), find the point Q

garri49 [273]

The point Q that partitions the line segment is Q(2,28)

Given that the directed line segment AB, with endpoints A(20, 6) and B(-16, 50) and divide the segment into a 1:1 ratio.

A line segment is a part of a line bounded by two distinct endpoints and containing all the points of the line segment between its endpoints.

We will find the point Q by using the section formula that is

Q(x,y)=((mx₂+nx₁)/(m+n),(my₂+ny₁)/(m+n))

The given ratio is m:n=1:1 and the points (x₁,y₁)=(20,6) and (x₂,y₂)=(-16,50).

Firstly, we will find the point Q for x-axis, we get

Q(x)=(mx₂+nx₁)/(m+n)

Q(x)=(1×(-16)+1×20)/(1+1)

Q(x)=(-16+20)/2

Q(x)=4/2

Q(x)=2

Now, we will find the point Q for y-axis, we get

Q(y)=(my₂+ny₁)/(m+n)

Q(y)=(1×50+1×6)/(1+1)

Q(y)=(50+6)/2

Q(y)=56/2

Q(y)=28

The point Q that partitions the line segment is Q(x,y)=(2,28)

Hence, point Q partitions this segment into a 1:1 ratio with directed line segment AB, with endpoints A(20, 6) and B(-16, 50) is Q(2,28).

Learn more about the line segment from here brainly.com/question/9034900

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2 years ago

X+2 = 7/8 mulltiplied by -15x

Marysya12 [62]

Answer:

x=16/113

Step-by-step explanation:

look at them in order

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3 years ago

What is the value of i 97 – i? –i 0 –2i i Superscript 96

Valentin [98]

The question is not clearly readable, but I'm assuming the expression which makes more sense, so you can have a clue

Answer:

$i^{97}-i=0$

Step-by-step explanation:

Powers of The Imaginary Unit

The imaginary unit i is defined as

$i=\sqrt{-1}$

The first powers of i are

$i^0=1$

$i^1=i$

$i^2=(\sqrt{-1})^2=-1$

$i^3=i.i^2=-i$

$i^4=i^2.i^2=1$

And so on the cycle repeats every four numbers. To find the value of $i^{96}$ we can find the remainder of 96/4=0. So $i^{96}=i^0=1$

The given expression is

$i^{97}-i$

Factoring

$i(i^{96}-1)$

Since $i^{96}=1$

$=i(1-1)=0$

The required value is 0

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