Answer:
t1 = $25m
t2 = $(10m + 100)
Step-by-step explanation:
Here we want to write equations
Kiera chose plan 1
$25 monthly and no joining fee
So the amount after m months will be 25 * m
t1 = $25m
Trina chose plan 2
$10 a month and $100 joining fee
after m months , total payment will be
10(m) + 100 = $(10m + 100)
Thus t1 = $25m and t2 = $(10m + 100)
Answer:
y = 7/2 -2
Step-by-step explanation:
if the slope of the first problem is -2/7 then its perpendicular is 7/2 (the exact opposite) and since the y- intercept is the b in Y= mx +b the intercept of the equation you’re trying to find is -2
Answer:
- 3*2=
Step-by-step explanation:
<u>Given</u><u> </u><u>that</u><u>,</u><u> </u>
x*y=
<h3>
<u>SO</u><u>,</u><u> </u></h3>
3*2=
<u>Therefore</u><u>:</u><u>-</u>
Hello! $200 is the fixed amount. B doesn't have 200 as part of the problem, so B is eliminated. A is also out, because you add, not subtract. 100 is the amount of boots made, not the amount made per pair of boots. 100 would be the value of "x". The cost per day is $9,200, and 9,200 - 200 is 9,000. With 100 pairs of boots being made each day, 9,000/100 is 90. It would cost $90 per pair of boots made, with the variable "x" being beside it. The correct equation would be C(x) = 90x + 200. The answer is D.
<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
