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Naya [18.7K]
3 years ago
9

What is the term to term for this question

Mathematics
1 answer:
mixas84 [53]3 years ago
7 0

In this equation x equals the number that came previously in the sequence.

The equation you need is ½x. That is the term to term for this question.

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Howie wants to get a car loan with 4% simple interest rate. If the car costs $25,000, how much would Howie need to pay back at t
likoan [24]

The amount Howie will pay back at the end of one year is $26000.00

The given parameters are:

P =25000 -- the principal amount

R = 4\% -- the interest rate

T=1 --- the duration

The amount to pay back in this duration is then calculated using:

A = P(1 + RT)

So, we have:

A = 25000(1 + 4\% \times 1)

A = 25000(1 + 4\% )

Express percentage as decimal

A = 25000(1 + 0.04)

A = 25000(1 .04)\\

Multiply

A = 26000

Hence, the amount to pay back is $26000.00

Read more about simple interest at:

brainly.com/question/1115815

7 0
3 years ago
the length of an arc of a circle is 1/5 of its circumference. if the area of the circle is346.5cm²,find the angle subtended by t
dexar [7]

Answer:

72°

Step-by-step explanation:

From the question,

Area of the circle = πr²

A = πr²................. Equation 1

Where r = radius of the circle.

⇒ r = √(A/π)............. Equation 2

Given: A = 346.5 cm², π = 3.14

r = √(346.5/3.14)

r = √(110.35)

r = 10.5 cm.

Therefore,

circumference of the circle = 2πr = 2×3.14×10.5

circumference = 65.94 m

If the length of the arc(s) is 1/5 of its circumference.

Therefore, length of arc (s) = 13.188

⇒ length of arc/circumference = 13.188/65.94 =  1/5

s/2πr = θ/360

Where θ = angle substends at the center of the circle

1/5 = θ/360

θ = 360/5

θ = 72°

3 0
3 years ago
Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x/6x^2 +
timama [110]

Looks like your function is

f(x)=\dfrac x{6x^2+1}

Rewrite it as

f(x)=\dfrac x{1-(-6x^2)}

Recall that for |x|, we have

\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n

If we replace x with -6x^2, we get

f(x)=\displaystyle x\sum_{n=0}^\infty\frac(-6x^2)^n=\sum_{n=0}^\infty (-6)^n x^{2n+1}

By the ratio test, the series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(-6)^{n+1} x^{2(n+1)+1}}{(-6)^n x^{2n+1}}\right|=6|x^2|\lim_{n\to\infty}1=6|x|^2

Solving for x gives the interval of convergence,

|x|^2

We can confirm that the interval is open by checking for convergence at the endpoints; we'd find that the resulting series diverge.

3 0
3 years ago
What value of x makes this equation true , use numerals instead of words.<br> -2x+3=-15
uysha [10]

Answer:

x = 9

Step-by-step explanation:

-2x + 3 = -15

-2x = -18

x = 9

7 0
2 years ago
Read 2 more answers
Solve the formula for t.<br> d = rt<br> Pls help easy branliest if right
Kay [80]

Answer:

t=d/r

Explanation:

Dived both sides by r

7 0
3 years ago
Read 2 more answers
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