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2 years ago

Find the volume of the figure. Round to nearest hundredth. *

Mathematics

1 answer:

hoa [83]2 years ago

8 0

Answer:

6 mi

Step-by-step explanation:

I think so it 6mi I need help

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Easiest question in the world no joke this time

Volgvan

Question #25:

One way to solve this is by multiplying the number of packages per serving by the number of guests.

1/4 * 16 = 4 packages to serve 16 guests. This means he doesn't have enough.

A second way to solve this is by diving the number of packages by the number of packages it takes to make on serving.

3 1/2 ÷ 1/4 = 14 guests he can serve. This means he doesn't have enough.

Question #26:

First, find common denominators.

2/3 = 8/12

1/4 = 3/12

Second, subtract.

8/12 - 3/12 = 5/12

Therefore, the tank is 5/12 full at the end of the trip.

Question #27:

1/2 is cut off then 1/3 is cut off. This means 3/6 was cut off to bundle newspapers, then 1/6 was cut off to make parcel. In all, 4/6 was cut off the original string. Afterwards, 2/6 was left over. So, just multiply; 2 * 3 = 6.

Therefore, the original string was as a total of 6 meters.

Best of Luck!

3 0

2 years ago

9*10^7 is how many times as large as 3*10^3 Please help

sesenic [268]

Answer:

30000 times larger.

Step-by-step explanation:

10^7 * 9/10^3*3

Law of exponents cancel some of the tens.

10^4 * 9/3

Cancel out the three.

10^4 *3

Compute

30000 times larger.

4 0

3 years ago

What is the greatest common factor of (8x-6)

bija089 [108]

Answer:

Step-by-step explanation:

(8x-6)

=2(4x-3)

5 0

3 years ago

A number y is 6 less than twice a number

omeli [17]

Answer:

Step-by-step explanation:

blah blah blah blah blah blah

7 0

3 years ago

How would the factor pairs change if nancy had only 5 posters to arrange?

Romashka [77]

Answer:

Part A) Nancy can arrange the posters in 4 ways

Part B) Nancy can arrange the posters in 2 ways

Step-by-step explanation:

<u><em>The complete question is</em></u>

Nancy has 10 movie posters. She wants to hang them on a wall in equals rows.

A) Find all the ways that she can arrange the posters.

B) How would the factor pairs change if Nancy had only 5 posters to arrange?

Part A) Find all the ways that she can arrange the posters.

we know that

The factors of 10 are

1x10 -----> 1 row of 10 posters

2x5 -----> 2 rows of 5 posters

5x2 -----> 5 rows of 2 posters

10x1 -----> 10 rows of 1 poster

therefore

Nancy can arrange the posters in 4 ways

Part B) How would the factor pairs change if Nancy had only 5 posters to arrange?

we know that

if Nancy had only 5 posters to arrange

then

The factors of 5 are

1x5 -----> 1 row of 5 posters

5x1 -----> 5 rows of 1 poster

therefore

Nancy can arrange the posters in 2 ways

3 0

2 years ago