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3 years ago

What is pi minus 6/5 pi in a fraction

Mathematics

1 answer:

maria [59]3 years ago

8 0

Negative pi over 5

− π/ 5

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HELP ME PLZZZZZZZZZZZZZZZZZ

murzikaleks [220]

The correct answer is 4

4 0

3 years ago

Read 2 more answers

fladli sells televisions. He earns a fixed amount for each television and an additional $ 20 if the buyer gets an extended warra

ivanzaharov [21]

Answer: $80

Step-by-step explanation:

Given: The amount earned by Fadil on selling 14 televisions= $1400

Therefore, the amount he earned on selling 1 television= $\frac{1400}{14}=\$100$

Since, he sold televisions with extended warranty and he earns $20 additional for it.

Then, the fixed amount Fadil earns for each television= $\$100-\$20=\$80$

Hence, Fadil earns $80 as the fixed amount for each televison.

4 0

4 years ago

How can 3/7 divided by 2/4 be written in simplest form?

vova2212 [387]

Presenting your problem symbolically:

3
--
7

==== becomes
2
---
4

3
---
7

====

1
---
2

To divide by 1/2, multiply by 2/1:

3 2
-- * ---
7 1

Multiplying, we get 6/7.

5 0

4 years ago

A deep-sea exploring ship is pulling up a diver at the rate of 25 feet per

avanturin [10]

Sorryyyyyyyyyyyyyyyy but try adding

3 0

3 years ago

An investment services company experienced dramatic growth in the last two decades. The following models for the company's reven

zlopas [31]

Answer: a) 138.32 and b) 35 years approx.

Step-by-step explanation:

Since we have given that

$R(t)=21.4e^{0.13t}\\\\C(t)=18.6e^{0.13t}$

So, Profit is given by

$Profit=R(t)-C(t)\\\\Profit=21.4e^{0.13t}-18.6e^{0.13t}\\\\Profit=e^{0.13t}(21.4-18.6)\\\\Profit=2.8e^{0.13t}$

Difference in years of 1990 and 2020=30

So, Profit becomes :

$P(30)=2.8e^{0.13\times 30}\\\\P(30)=2.8\times 49.40\\\\P(30)=138.32$

(b) How long before the profit found in part (a) is predicted to double? (Round your answer to the nearest whole number.) years after 1990.

So, profit doubles , we get :

$138.32\times 2=2.8e^{0.13t}\\\\276.65=2.8e^{0.13t}\\\\\dfrac{276.65}{2.8}=e^{0.13t}\\\\98.80=e^[0.13t}\\\\\ln 98.80=0.13t\\\\4.593=0.13t\\\\\dfrac{4..593}{0.13}=t\\\\35.33=t$

Hence, a) 138.32 and b) 35 years approx.

6 0

3 years ago