Answer:

Step-by-step explanation:
×
= 
(
)² =
= 
Answer:
Some of the applications for exponential functions are:
1. model populations
2. carbon date artifacts
3. compound interest
hope this helps!
Answer:
Step-by-step explanation:
To find the area subtract the area of the semicircle from the area of the rectangle.
Although the line isn’t there, if you imagine there is one, then you will see that you form a rectangle which is the same line as the semicircle’s diameter.
The area of rectangle is:
⇒ 
⇒ 
⇒ 
The area of the semicircle;
⇒ 
⇒ 
*Note here that the radius is half the diameter, so it is 7cm, not 14cm
⇒ 
Finally subtract the two areas;
⇒ 
⇒ 
12 meters longer than his throw should be t + 12
t + 12 is your answer
hope this helps