Slope = (5+8)/(8-4) = 13/4
y = mx + b
b= y - mx
b = -8 - (13/4) (4)
b = -8 -13
b = -21
equation
y = 13/4x - 21
Answer:
(5,2,2)
Step-by-step explanation:
-3x+4y+2z = -3
2x-4y-z=0
y = 3x-13
Multiply the second equation by 2
2*(2x-4y-z)=0*2
4x -8y -2z =0
Add this to the first equation to eliminate z
-3x+4y+2z = -3
4x -8y -2z =0
-------------------------
x -4y = -3
Take the third equation and substitute it in for y
x - 4(3x-13) = -3
Distribute the 4
x - 12x +52 = -3
Combine like terms
-11x +52 = -3
Subtract 52 from each side
-11x +52-52 = -3-52
-11x = -55
Divide by -11
-11x/-11 = -55/-11
x=5
Now we can solve for y
y =3x-13
y =3*5 -13
y = 15-13
y=2
Now we need to find z
2x-4y-z=0
2(5) -4(2) -z=0
10-8 -z=0
2-z=0
Add z to each side
2-z+z= 0+z
2=z
x=5, y=2, z=2
(5,2,2)
Answer:
y = -6x + 10
Step-by-step explanation:
Parallel lines share the same slope. Given y = -6x – 1, we know that the equation of this new line has the form y = -6x – C. The coordinates of the point (1, 4) determine the value of C:
(4) = -6(1) – C, or:
4 = -6 - C
Then C = -10, and the desired equation is
y = -6x – (-10), or
y = -6x + 10
Answer:
D = .44P
Step-by-step explanation:
We need to find the slope of the line
m = (y2-y1)/ (x2-x1)
Using two points
m = (22-4.4) /(50-10)
= 17.6/40
= .44 lb/ in^2 ft
We can use the point slope form of the equation
y-y1 = m(x-x1) where y=D and x=P
D-4.4 = .44 (P-10)
Distribute
D-4.4 = .44P - 4.4
Add 4.4 to each side
D -4.4+4.4 = .44P -4.4+4.4
D = .44P
Simplify \frac{5}{3}x35x to \frac{5x}{3}35x
x-\frac{5x}{3}<3x−35x<3
2
Simplify x-\frac{5x}{3}x−35x to -\frac{2x}{3}−32x
-\frac{2x}{3}<3−32x<3
3
Multiply both sides by 33
-2x<3\times 3−2x<3×3
4
Simplify 3\times 33×3 to 99
-2x<9−2x<9
5
Divide both sides by -2−2
x>-\frac{9}{2}x>−29
