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2 years ago

Solve for the value of x and y when 3x+2y=24 , x+y=9 step wise explanation plz

Mathematics

2 answers:

OLga [1]2 years ago

6 0

Answer:

{x,y} = {2,9}

Step-by-step explanation:

Solve equation [2] for the variable y

[2] 2y = -6x + 30

[2] y = -3x + 15

// Plug this in for variable y in equation [1]

[1] 3x + 2•(-3x+15) = 24

[1] -3x = -6

// Solve equation [1] for the variable x

[1] 3x = 6

[1] x = 2

// By now we know this much :

x = 2

y = -3x+15

// Use the x value to solve for y

y = -3(2)+15 = 9

grigory [225]2 years ago

4 0

This is what I got. Tell me if I got it wrong.

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Giving brainliest and max rating.

Yanka [14]

Given:

The cost of each carnival ticket is $5.

To find:

The equation, table of values and graph for the given problem.

Solution:

Let x be the number of tickets and y be the total money spent on tickets.

Cost of one ticket = $5

Cost of x tickets = $5x

So, total cost is

$y=5x$

The required equation is $y=5x$ .

At x=1,

$y=5(1)$

$y=5$

At x=2,

$y=5(2)$

$y=10$

At x=3,

$y=5(3)$

$y=15$

The required table of values is

x y

1 5

2 10

3 15

So, the required table of values is table A.

From the above table, it is clear that the graph passes through the point (1,5), (2,10) and (3,15). The graph B passes through these points.

So, the required graph is graph B.

Since the required answers are $y=5x$ , table A, graph B, therefore the correct option is B.

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3 years ago

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Vlad1618 [11]

Answer:

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Step-by-step explanation:

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3 years ago

Write 3x^2-18x-6 in vertex form

Vedmedyk [2.9K]

The standard form of a quadratic equation is $\displaystyle{ y=ax^2+bx+c$ , while the vertex form is:

$y=a(x-h)^2+k$ , where (h, k) is the vertex of the parabola.

What we want is to write $\displaystyle{ y=3x^2-18x-6$ as $y=a(x-h)^2+k$

First, we note that all the three terms have a factor of 3, so we factorize it and write:

$\displaystyle{ y=3(x^2-6x-2)$ .

Second, we notice that $x^2-6x$ are the terms produced by $(x-3)^2=x^2-6x+9$ , without the 9. So we can write:

$x^2-6x=(x-3)^2-9$ , and substituting in $\displaystyle{ y=3(x^2-6x-2)$ we have:

$\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]$ .

Finally, distributing 3 over the two terms in the brackets we have:

$y=3[x-3]^2-33$ .

Answer: $y=3(x-3)^2-33$