Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
Answer:
Hi! The answer to your question is Slope: 0, Y-Intercept: 3
Step-by-step explanation:
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Answer:
i pretty sure i do not know that answer to be honest
Step-by-step explanation:
i believe this because i dont know anything about this im still lost
<span><u><em>The correct answer is:</em></u>
2.
<u><em>Explanation</em></u><span><u><em>:</em></u>
20 hundreds =20*100=2000;
this is two thousand, so it is made of 2 thousands.</span></span>
