All categories

3 years ago

The perimeter of a rectangle is 24 in.and its length is 3times its width. What are the length and width of ThE rectangle?

Mathematics

2 answers:

Mama L [17]3 years ago

8 0

let w = width and 3w = length

perimeter is the distance around the outside of the object or P = 2L + 2W

2(3w) + 2w = 24

6w + 2w= 24

8w = 24

w= 3

3w= 9

Width is 3in. and length is 9in.

ivann1987 [24]3 years ago

3 0

The length is 9 and the width is 3

You might be interested in

Simplify (7x2 - 2x + 9) + (3x2 + 15x – 4).

VikaD [51]

Hey! Your answer for this is

7x^2 + 3x^2 = 10x^2

-2x + 15x = 13x

9 - 4 = 5

Hence, 10x^2 + 13x + 5.

Hope this helps!

5 0

4 years ago

Read 2 more answers

Which fraction is equivalent to 9 12

polet [3.4K]

The equivalent is 3/4. It’s reduced.

3 0

3 years ago

Read 2 more answers

What is the value of the underlined -195

motikmotik

What number is underlined??????

4 0

3 years ago

Read 2 more answers

Explain how you can use a number line to show that 5/8isgreater than 3/8

Rina8888 [55]

Here is what I did....

8 0

4 years ago

Find the general solution to 1/x dy/dx - 2y/x^2 = x cos x, y(pi) = pi^2

Finger [1]

Answer:

$\frac{y}{x^2}=\sin x+\pi$

Step-by-step explanation:

Consider linear differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$

It's solution is of form $y\,I.F=\int I.F\,q(x)\,dx$ where I.F is integrating factor given by $I.F=e^{\int p(x)\,dx}$ .

Given: $\frac{1}{x}\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x^2}=x\cos x$

We can write this equation as $\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{2y}{x}=x^2\cos x$

On comparing this equation with $\frac{\mathrm{d} y}{\mathrm{d} x}+yp(x)=q(x)$ , we get $p(x)=\frac{-2}{x}\,\,,\,\,q(x)=x^2\cos x$

I.F = $e^{\int p(x)\,dx}=e^{\int \frac{-2}{x}\,dx}=e^{-2\ln x}=e^{\ln x^{-2}}=\frac{1}{x^2}$ { formula used: $\ln a^b=b\ln a$ }

we get solution as follows:

$\frac{y}{x^2}=\int \frac{1}{x^2}x^2\cos x\,dx\\\frac{y}{x^2}=\int \cos x\,dx\\\\\frac{y}{x^2}=\sin x+C$

{ formula used: $\int \cos x\,dx=\sin x$ }

Applying condition: $y(\pi)=\pi^2$

$\frac{y}{x^2}=\sin x+C\\\frac{\pi^2}{\pi}=\sin\pi+C\\\pi=C$

So, we get solution as :

$\frac{y}{x^2}=\sin x+\pi$

4 0

3 years ago