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fredd [130]
3 years ago
11

A cylindrical tank has a height of 12 feet and a diameter of 16 feet. Jane fills the tank with water at a rate of 6 cubic feet p

er minute. Calculate how long it would take Jane to fill the tank without overflowing it. Explain your reasoning. Round as needed.
Mathematics
1 answer:
cupoosta [38]3 years ago
4 0
If the diameter is 16 feet, then the radius for the tank will have to be half that, 

\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=8\\
h=12
\end{cases}\implies V=\pi \cdot 8^2\cdot 12\implies V=\stackrel{ft^3}{768\pi}

now, that's how many ft³ of water the tank can hold, since she is filling it up at a rate of 6 ft³ per minute, namely in 1 minute 6 ft³ have gone in, then it'll be

768π/6  how many minutes it'll take.

namely, how many times does 6 go into 768π?  well, 768π/6.
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What is the value of X in the isosceles trapezoid below?
valina [46]
Solve using your rules:

180 = 9x + 4x + 37

That means 143 = 13x

Thus x = 11
8 0
3 years ago
The hypotenuse of a right triangle is 37 units long. Find the other two sides if the perimeter of the triangle is 84 units. Sepa
taurus [48]

Answer:

The lengths of the legs are 12 and 35 units

Step-by-step explanation:

Let c represent the hypotenuse and a and b represent the legs.  Then the Pythagorean Theorem requires that a^2 + b^2 = c^2 = 37^2 = Hypotenuse^2

Also:  a + b + c = Perimeter = 84 units.  

Since c = 37 units, a + b + 37 units = 84 units, or a + b = 47 units, or a = 47 - b.

Then a^2 + b^2 = 37^2 becomes (47 - b)^2 + b^2 = 37^2, or 1369.  Therefore:

2209 - 94b + b^2 + b^2 = 1369.

Simplifying by combining like terms, we get:  

840 - 94b + 2b^2 = 0, which is a quadratic equation in standard form.

Reducing all terms by division by 2, we get:

420 - 47b + b^2 = 0.  Here the coefficients are a = 1, b = -47 and c = 420.

The discriminant is therefore b^2 - 4ac, or 529, whose square root is ± 23.

Then the b values of this quadratic in b are

      47 ± 23

b = -------------- , so that b is either 35 or 12

             2

and then side a has length a = 47 - b = 12  or  35.

Thus, a = 12 and b = 35, and c is given:  37.

Check:  Is 12^2 + 35^2 = 37^2 true?  Is 144 + 1225 = 1369?  YES

The lengths of the legs are 12 and 35 units.

7 0
3 years ago
. Find the area of the regular dodecagon inscribed in a circle if one vertex is at (3, 0).
devlian [24]

Answer:

Area of the regular dodecagon inscribed in a circle will be 27 square units.

Step-by-step explanation:

A regular dodecagon is the structure has twelve sides and 12 isosceles triangles inscribed in a circle as shown in the figure attached.

Since angle formed at the center by a polygon = \frac{360}{n}

Therefore, angle at the center of a dodecagon = \frac{360}{12} = 30°

Since one of it's vertex is (3, 0) therefore, one side of the triangle formed or radius of the circle = 3 units

Now area of a small triangle = \frac{1}{2}.(a).(b).sin\theta

where a and b are the sides of the triangle and θ is the angle between them.

Now area of the small triangle = \frac{1}{2}.(3).(3).sin30

= \frac{9}{4}

Area of dodecagon = 12×area of the small triangle

= 12×\frac{9}{4}

= 27 unit²

Therefore, area of the regular octagon is 27 square unit.

4 0
3 years ago
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