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madreJ [45]
3 years ago
12

A box of fruit has three times as many nectarines as grapefruit. Together there are 64 pieces of fruit. Write the equation that

represents this situation.
Mathematics
1 answer:
Basile [38]3 years ago
7 0

Answer:

4g = 64

Step-by-step explanation:

Let n = the number of nectarines

and g = the number of grapefruit

We have two conditions that must be satisfied to represent the situation:

(1)         n = 3g

(2) n + g = 64

If you need one equation, we can substitute (1) into (2) and get

4g = 64

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Ralph is 3 times as old as Sara. In 4 years, Ralph will be only twice as old as Sara will be then. Find Ralph's age now. Ralph's
IgorLugansk [536]
Let
R = Ralph's age
S = Sara's age

First statement is translated as:
S = 3R

Second statement is translated as:
S + 4 = 2(R + 4)

Use the first equation to be substituted into the second one in terms of R which is the one we are actually going to solve for Ralph's age.
Since S = 3R, then
3R + 4 = 2(R + 4)
3R + 4 = 2R + 8
3R - 2R = 8 - 4
R = 4 years old
7 0
3 years ago
Read 2 more answers
Using long division to find the quotient and remainder 4x^4+2x^2-2 divided by x^2+2
emmasim [6.3K]
                             4x²    -6
         __________________
x²+2  l 4x^4         +2x²     -2
         l  4x^4        +8x²
           --------------------
                            -6x²     -2
                            -6x²     -12
                           ---------------
                                       10

so the answer is (4x^2-6) \frac{10}{x^2+2}
8 0
3 years ago
Graph the hyperbola using the transverse axis, vertices, and co-vertices:
Reptile [31]

See attachment for the graph of the hyperbola 12x^2 - 3y^2 - 108 = 0

<h3>How to graph the hyperbola?</h3>

The equation of the hyperbola is given as:

12x^2 - 3y^2 - 108 = 0

Start by calculating the transverse axis

So, we have:

<u>Transverse axis</u>

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

Where

a = 3 and b = 6

The transverse axis is calculated as:

y = ±b/a(x - h) + k

So, we have:

y = ±6/3(x - 0) + 0

Evaluate the difference and sum

y = ±6/3x

Evaluate the quotient

y = ±2x

This means that the transverse axes are y = 2x and y =-2x

<u>The vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

<u>The co-vertices</u>

In the above section, we have:

The vertices of the given hyperbola are (0, 0)

This means that

(h, k) = 0

And

a = 3 and b = 6

The co-vertices are

(h - a, k) and (h + a, k)

So, we have:

(0 - 3, 0) and (0 + 3, 0)

Evaluate

(-3,0) and (3, 0)

See attachment for the graph of the hyperbola

Read more about hyperbola at:

brainly.com/question/26250569

#SPJ1

4 0
1 year ago
What is the percent error
RideAnS [48]
When you don't use or write the percent right.<span />
8 0
3 years ago
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Solve the equation for y.<br> 10x -4y = -20
Vinvika [58]

Answer:

y=5+5/2x

Step-by-step explanation:

7 0
3 years ago
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