Answer:
The proof is explained step-wise below :
Step-by-step explanation :
For better understanding of the solution see the attached figure :
Given : ABCD is a Parallelogram ⇒ AB ║ DC and AD ║ BC
Now, F lies on the extension of DC. So, AB ║ DF
To Prove : ΔABE is similar to ΔFCE
Proof :
Now, in ΔABE and ΔFCE
∠ABE = ∠FCE ( alternate angles are equal )
∠AEB = ∠FEC ( Vertically opposite angles )
So, by using AA postulate of similarity of triangles
ΔABE is similar to ΔFCE
Hence Proved.
Answer:
4.7
Step-by-step explanation:
The red I think is hinting to the x.
The given equation is
We need to solve the equation for q.
<u>Value of q:</u>
The value of q can be determined by solving the equation
for q.
Thus, subtracting both sides of the equation by r, we get;

Now, dividing both sides of the equation by b, we have;

Simplifying the terms, we get;

Therefore, the value of q is 
Hence, Option B is the correct answer.
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