PLEASE HELP ILL GIVE BRAINLIEST
2 answers:
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If the equation is passing trough the origin, it will be passing trough the point (0,0). We now for our problem that the equations is also passing trough the point (-4,3). So, our line is passing trough the points (0,0) and (-4,3). To write the equation in slope-intercept form, first, we need to find its slope 
. To do that we are going to use the slope formula: 
.
From our two points we can infer that
, 
, 
, 
. Lets replace those values in the slope formula:
Now that we have our slope, we can use the slope-intercept formula:
We can conclude that the equation of the line passing trough the points (0,0) and (-4,3) is.
From our two points we can infer that
Now that we have our slope, we can use the slope-intercept formula:
We can conclude that the equation of the line passing trough the points (0,0) and (-4,3) is
<h2>Steps:</h2>
So for this, I will be factoring by grouping. Firstly, factor x³ + 2x² and -4x - 8 separately. Make sure that they have the same quantity inside of the parentheses:
Now we can rewrite it as:
However, we aren't finished factoring yet. The first factor, x² - 4, can be factored further using the difference of squares. The difference of squares goes by the formula here: . In this case:
<u>In short, the answer is </u>