Answer:
=》n = 10
Step-by-step explanation:
here's the solution :-
=》
![2(n - 9) - 1 = 1](https://tex.z-dn.net/?f=2%28n%20-%209%29%20-%201%20%3D%201)
=》
![2(n - 9) = 1 + 1](https://tex.z-dn.net/?f=2%28n%20-%209%29%20%3D%201%20%2B%201)
=》
![2(n - 9) = 2](https://tex.z-dn.net/?f=2%28n%20-%209%29%20%3D%202)
=》
![n - 9 = \frac{2}{2}](https://tex.z-dn.net/?f=n%20-%209%20%3D%20%20%5Cfrac%7B2%7D%7B2%7D%20)
=》
![n - 9 = 1](https://tex.z-dn.net/?f=n%20-%209%20%3D%201)
=》
![n = 1 + 9](https://tex.z-dn.net/?f=n%20%3D%201%20%2B%209)
=》
![n = 10](https://tex.z-dn.net/?f=n%20%3D%2010)
hence, the value of n = 10
The rate of change aka slope is -2
Answer:
The experimental probability of rolling a 2 is
.
Step-by-step explanation:
Since you didn't give any statements, I'll make one myself.
P of rolling a 2 (experimental): ![\frac{15}{60} =\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B60%7D%20%3D%5Cfrac%7B1%7D%7B4%7D)
The experimental probability of rolling a 2 is
.
This is a transform fault. Although please post in the geography section next time!
Multiply the original DE by xy:
xy2(1+x2y4+1−−−−−−−√)dx+2x2ydy=0(1)
Let v=xy2, so that dv=y2dx+2xydy. Then (1) becomes
x(y2dx+2xydy)+xy2x2y4+1−−−−−−−√dxxdv+vv2+1−−−−−√dx=0=0
This final equation is easily recognized as separable:
dxxln|x|+CKxvKx2y2−1K2x4y4−2Kx2y2y2=−dvvv2+1−−−−−√=ln∣∣∣v2+1−−−−−√+1v∣∣∣=v2+1−−−−−√+1=x2y4+1−−−−−−−√=x2y4=2KK2x2−1integrate both sides