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Anni [7]
3 years ago
11

The diagnoal of a rectangle is 25 inches and the width is 15 inches what is the length

Mathematics
1 answer:
Grace [21]3 years ago
3 0

Answer:

20 inches

Step-by-step explanation:

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402 = 2 x 3 x ____<br> help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Westkost [7]

Answer:

67

Step-by-step explanation:

2x3=6

402/6=67

2x3x67=402

hope this helped:)

5 0
3 years ago
There are 18 fish in a pond. 9 carp, 8 koi,
svetlana [45]

Answer:18/5

Step-by-step explanation:

7 0
3 years ago
What is the answer to 5.09x15
Lady bird [3.3K]

5.09 times 15 equals 76.35

4 0
3 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
Find the commission.<br> Earning Commission | sales = ​$530 | commision rate = 3​% | ​commision = ?
sergij07 [2.7K]

Answer:

$15. 90

Step-by-step explanation:

3% of 530= 15.9

4 0
3 years ago
Read 2 more answers
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