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3 years ago

5×10 to the ninth power

Mathematics

2 answers:

nikklg [1K]3 years ago

4 0

Answer:

5,000,000,000 or 1,953,125,000,000,000

Depends on what you mean

Step-by-step explanation:

If (5*10)^9

(50)^9

1,953,125,000,000,000

Or if 5 * (10)^9

5 * 1,000,000,000 = 5,000,000,000

denpristay [2]3 years ago

3 0

Answer:1953125 x 10^9

Step-by-step explanation: 5^9= 1953125 and 10^9.

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What are the coordinates of the centroid of a triangle with vertices A(−3, 1) , B(1, 6) , and C(5, 2)

Nataly_w [17]

The correct answer is

(1,3) is the centroid
Enter (1,3) in the boxes

4 0

3 years ago

Need help! Does anyone know how to do this type of math? (It's geometry)

mart [117]

Answer:

Step-by-step explanation:

refer the attachment

to solve the question we need to recall one of the most important theorem of circle known as two tangent theorem which states that tangents which meet at the same point are equal that is being said

FA=AI=17
CH=CG=2.5

since $\rm BA=FA+FB$ and it's given that FA and BA are 17 and 29 FB should be

$\rm 29=17+FB$

therefore,

$FB=29-17=\boxed{12}$

once again by two tangent theorem we acquire:

$FB=BH=\boxed{12}$

As BC=BH+CH,BC is

12+2.5
$\boxed{14.5}$

likewise,AD=AI+DI so,

21=17+DI [AD=21(given) and AI=17 (by the theorem)]

thus,

DI=21-17= $\boxed{4}$

By the theorem we obtain:

DI=DG=4

Similarly,DC=DG+CH therefore,

DC=4+2.5= $\boxed{6.5}$

Now finding the Perimeter of ABCD

$P_{\text{ABCD}}=\text{AB+AD+BC+DC}$

substitute what we have and got

$P_{\text{ABCD}}=\text{29+21+14.5+6.5}$

simplify addition:

$P_{\text{ABCD}}=\boxed{71}$

hence,

the Perimeter of ABCD is 71

4 0

2 years ago

a scuba diver descended at a rate of 2 1/4 per second. If 0 represents the surface of the water and distances below the surface

Shtirlitz [24]

Answer:

The location will be at $- 28\frac{1}{8}$ units.

Step-by-step explanation:

A scuba diver descended at a rate of $2\frac{1}{4}$ units per second.

Now, if 0 represents the surface of the water and distances below the surface are negative, then after $12\frac{1}{2}$ seconds the location of the diver will be given by the followings :