Answer:
It compresses up 2
Step-by-step explanation:
Answer:
30 baskets
Step-by-step explanation:
The experimental probability Pa that Amir will make a basket is 0.4;
Pa = 0.4
the experimental probability Pj that juju with make the same basket is 0.6;
Pj = 0.6
Total number of shoot Nt = 150
Number of basket Amir will make is;
Na = Pa × Nt
Na = 0.4 × 150
Na = 60 basket
Number of basket juju will make is;
Nj = Pj × Nt
Nj = 0.6 × 150
Nj = 90 basket
The height of the tank must be at least 1 foot, or 12 inches. We know the floor area (which is length x width) must be at least 400 inches. Therefore these minimum dimensions already tell us that the minimum volume is 400 x 12 = 4800 cubic inches. Since we have a maximum of 5000 cubic inches, the volume must be within the range of 4800 - 5000 cubic inches.
We can set the height at exactly 1 ft (or 12 inches). Then we can select length and width that multiply to 400 square inches, for example, L = 40 inches and W = 10 in. This gives us a tank of dimensions 40 x 10 x 12 = 4800 cubic inches, which fits all the criteria.
Givens
y = 2
x = 1
z(the hypotenuse) = √(2^2 + 1^2) = √5
Cos(u) = x value / hypotenuse = 1/√5
Sin(u) = y value / hypotenuse = 2/√5
Solve for sin2u
Sin(2u) = 2*sin(u)*cos(u)
Sin(2u) = 2(
) = 4/5
Solve for cos(2u)
cos(2u) = - sqrt(1 - sin^2(2u))
Cos(2u) = - sqrt(1 - (4/5)^2 )
Cos(2u) = -sqrt(1 - 16/25)
cos(2u) = -sqrt(9/25)
cos(2u) = -3/5
Solve for Tan(2u)
tan(2u) = sin(2u) / cos(2u) = 4/5// - 3/5 = - 0.8/0.6 = - 1.3333 = - 4/3
Notes
One: Notice that you would normally rationalize the denominator, but you don't have to in this case. The formulas are such that they perform the rationalizations themselves.
Two: Notice the sign on the cos(2u). The sin is plus even though the angle (2u) is in the second quadrant. The cos is different. It is about 126 degrees which would make it a negative root (9/25)
Three: If you are uncomfortable with the tan, you could do fractions.

Answer:

Step-by-step explanation:
An ellipse centered a point (h,k) has the following formula:

The distance between foci is:
![2\cdot c = \sqrt{[8-(-8)]^{2}+(0-0)^{2}}](https://tex.z-dn.net/?f=2%5Ccdot%20c%20%3D%20%5Csqrt%7B%5B8-%28-8%29%5D%5E%7B2%7D%2B%280-0%29%5E%7B2%7D%7D)


The center of the ellipse is:


The known vertex is on the horizontal axis of the ellipse. Then, the length of the semi-major axis is:


The length of the semi-minor axis is given by the following expression:




The equation of the ellipse is:
