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melomori [17]
3 years ago
10

Factor completely, then place the factors in the proper location on the grid. x^2n + 10x^n + 16

Mathematics
1 answer:
postnew [5]3 years ago
7 0

Answer:

(x^n + 2)(x^n + 8)

Step-by-step explanation:

The polynomial x^{2n}+10x^n + 16 can be factored exactly the same as the polynomial x^2 + 10x + 16. Here it factors into two numbers which multiply to 16 but add to 8. These factors are 8 and 2. So it factors into the expression (x+8)(x+2).

For the polynomial x^{2n}+10x^n + 16 it factors into the same factors except x ^n is used instead. The factors are (x^n + 2)(x^n + 8)

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7. If U= {2, 4, 6, 8, 10, 12, 14, 16} and<br> A = {6, 10, 14}, what is A'?
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The compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

We are given the universal set as:

U = {2, 4, 6, 8, 10, 12, 14, 16}

We are also given that set A is:

A = {6, 10, 14}

We need to find A'

For this, we will subtract set A from the universal set, U.

So, we get that:

A' = U - A

A' = {2, 4, 6, 8, 10, 12, 14, 16} - {6, 10, 14}

Solving the expression, we get that:

A' = {2, 4, 8, 12, 16}

Therefore, we get that, the compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

Learn more about sets here:

brainly.com/question/2166579

#SPJ9

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