All categories

3 years ago

21/49 in lowest terms

Mathematics

2 answers:

slega [8]3 years ago

8 0

21/49

Divide numerator and denominator by GCF.

GCF = 7

21 ÷ 7 = 3
49 ÷ 7 = 7
3/7

21/49 in lowest terms is 3/7.

noname [10]3 years ago

5 0

21/49 in lowest terms

1) To make a fraction in lowest terms you have to divide by the greatest common factor.

The GCF of 21 and 49 is 7

2) Simplify Fraction

Divide the numerator and denominator by 7

21 ÷ 7 = 3
49 ÷ 7 = 7

21/49 in lowest terms is 3/7

You might be interested in

OLZ HELP ILL MARK AS BRAINLEST Find the slope of the line that goes through the following points

Artist 52 [7]

Answer:

B. 1 :)

Step-by-step explanation:

Every time the x value gets bigger, the y laue does too. Positive numbers are larger than negative ones so every time we get closer to 0, our values get bigger :)

Have an amazing day!!

Please rate and mark as brainliest!!

7 0

2 years ago

A gas station stores its gasoline in a tank under the ground. The tank is a cylinder lying horizontally on its side. (In other w

julsineya [31]

Answer:I write the answer in the paper

Step-by-step explanation:

8 0

3 years ago

Enter the expression using exponents. 1\2 × 1\2 × 1\2 × 1\2 × 1\2 × 1\2 × 1\2

Ad libitum [116K]

Answer:

Step-by-step explanation:

1/2 is multiplied by itself 7 times, thus an exponent of 7.

I'm always happy to help :)

3 0

3 years ago

Read 2 more answers

Hypothesis Testing

Yuri [45]

Answer:

Problem 1: We conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

Problem 2: We conclude that the volume of Google stock has changed.

Step-by-step explanation:

Problem 1:

We are given that in a recent survey conducted by Pew Research, it was found that 156 of 295 adult Americans without a high school diploma were worried about having enough saved for retirement.

Let p = proportion of adult Americans without a high school diploma who are worried about having enough saved for retirement

So, Null Hypothesis, $H_0$ : p $\leq$ 50% {means that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement}

Alternate Hypothesis, $H_A$ : p > 50% {means that a majority of adult Americans without a high school diploma are worried about having enough saved for retirement}

This is a right-tailed test.

The test statistics that would be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adult Americans who were worried about having enough saved for retirement = $\frac{156}{295}$ = 0.53

n = sample of adult Americans = 295

So, the test statistics = $\frac{0.53-0.50}{\sqrt{\frac{0.50(1-0.50)}{295} } }$

= 1.03

The value of z-test statistics is 1.03.

Also, the P-value of the test statistics is given by;

P-value = P(Z > 1.03) = 1 - P(Z $\leq$ 1.03)

= 1 - 0.8485 = 0.1515

Now, at a 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is less than the critical value of z as 1.03 < 1.645, so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that less than or equal to 50% of adult Americans without a high school diploma are worried about having enough saved for retirement.

Problem 2:

We are given that a random sample of 35 trading days in 2014 resulted in a sample mean of 3.28 million shares with a standard deviation of 1.68 million shares.

Let $\mu$ = mean daily volume in Google stock

So, Null Hypothesis, $H_0$ : $\mu$ = 5.44 million shares {means that the volume of Google stock has not changed}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ 5.44 million shares {means that the volume of Google stock has changed}

This is a two-tailed test.

The test statistics that would be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean volume in Google stock = 3.28 million shares

s = sample standard deviation = 1.68 million shares

n = sample of trading days = 35

So, the test statistics = $\frac{3.28-5.44}{\frac{1.68}{\sqrt{35} } }$ ~ $t_3_4$

= -7.606

The value of t-test statistics is -7.606.

Also, the P-value of the test statistics is given by;

P-value = P( $t_3_4$ < -7.606) = Less than 0.05%

Now, at a 0.05 level of significance, the t table gives a critical value of -2.032 and 2.032 at 34 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the volume of Google stock has changed.

8 0

3 years ago

Suppose the price of admission to the state fair is $9.50, and each ride costs an additional $2.25.

alexandr402 [8]

Answer:

Step-by-step explanation:

You need to multiply the variable by how much each ride costs.

3 0

3 years ago