All categories

2 years ago

Please help me. im dying

Mathematics

1 answer:

inna [77]2 years ago

4 0

Answer:

19/37

Step-by-step explanation:

47/148 + 29/148 = 76/148 = 38/74 = 19/37

You might be interested in

Plzzzz help I know yall see it and there are some of yall who know this stuff so plzzzz help!!!!!! Pic down below!!

allochka39001 [22]

Ugggggggg idk soooooooo yeah

5 0

3 years ago

Find out the product of 2,12 and 3

drek231 [11]

You mean 2x3x12? if yes, it is 72.

8 0

3 years ago

Read 2 more answers

A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop

Katyanochek1 [597]

Answer: $(0.367,\ 0.473)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ is the sample proportion, n is the sample size , $z_{\alpha/2}$ is the critical z-value.

Given : Significance level : $\alpha:1-0.99=0.01$

Sample size : n= 85

Critical value : $z_{\alpha/2}=2.576$

Sample proportion: $\hat{p}=\dfrac{36}{85}\approx0.42$

Now, the 99% confidence level will be :

$\hat{p}\pmz_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.42\pm(2.576)\sqrt{\dfrac{0.42(1-0.42)}{85}}\\\\\approx0.42\pm0.053\\\\=(0.42-0.053,\ 0.42+0.053)=(0.367,\ 0.473)$

Hence, the 99% confidence interval estimate of the true proportion of families who own at least one DVD player is $(0.367,\ 0.473)$

3 0

2 years ago

Im throwing tons of points for these questions so please help

Galina-37 [17]

10. x = 4,-4

11. x = 2,-2

12. Length = 12 yards, Weight = 6 yards

13. x = -5,2

3 0

3 years ago

Read 2 more answers

Two vertical poles of lengths 11 ft and 14 ft stand 16 ft apart. A cable reaches from the top of one pole to some point on the g

Alex17521 [72]

We are given

total length of cable is 30 feet

and this cable is on hypotenuse sides of the triangles

so, we can draw triangle as

Let's assume those hypotenuse as 'a' and 'b'

so, we will have

$a+b=30$

now, we can find 'a' and 'b' from triangle

Smaller triangle:

$a=\sqrt{x^2+11^2}$

Larger triangle:

$b=\sqrt{(16-x)^2+14^2}$

we know that

$a+b=30$

so, we can plug this value

and we get

$\sqrt{x^2+11^2}+\sqrt{(16-x)^2+14^2} =30$

now, we can solve for x

$\left(\sqrt{x^2+11^2}\right)^2=\left(30-\sqrt{\left(16-x\right)^2+14^2}\right)^2$

$32x-1231=-60\sqrt{x^2-32x+452}$

$1024x^2-78784x+1515361=3600x^2-115200x+1627200$

now, we can use quadratic formula

we get

$x=\frac{-\sqrt{36416^2-1152389056}+36416}{5152},\:x=\frac{\sqrt{36416^2-1152389056}+36416}{5152}$

$x=4.510,x=9.627$

so,

The point should be located 4.510 feet , 9.627 feet from the smaller pole to use 30 feet cable............Answer

6 0

3 years ago