1. 7 and -7 are both 7 units away from 0. They are 14 units away from each other. Absolute value helps because rather than 7+(-7) being 0 absolute value makes anything positive so it becomes 7+7=14 to be able to count the units between the two.
2. 5 and -5 are both 5 units away from 0. They are 10 units away from each other. Absolute value helps because rather than 5+(-5) being 0 absolute value makes anything positive so it becomes 5+5=10 to be able to count the units between the two.
3. 2 and -2 are both 2 units away from 0. They are 4 units away from each other. Absolute value helps because rather than 2+(-2) being 0 absolute value makes anything positive so it becomes 2+2=4 to be able to count the units between the two.
Hope that helps
Answer:
The area of an octagon whose perimeter is 120 cm is 1086.4 
Step-by-step explanation:
An octagon is a polygon with eight sides. If the lengths of all the sides and the measurement of all the angles are equal, the octagon is called a regular octagon.
There is a predefined set of formulas for the calculation of perimeter, and area of a regular octagon.
The perimeter of an Octagon is given by

and the area of an Octagon is given by

We know that the perimeter is 120 cm, solving for side length (a) in the perimeter formula we get

Now, we calculate the area

Answer:
The x-intercept is -2
Step-by-step explanation:
Answer:
perimeter = 20 m
Step-by-step explanation:
given the area of the square = 25 m² and
area of a square = s² ( where s is the side length ), then
s² = 25 ( take the square root of both sides )
s =
= 5 ← length of side
perimeter = 4s = 4 × 5 = 20 m