All categories

3 years ago

4(x-.50)=x*3 Show your work

Mathematics

2 answers:

den301095 [7]3 years ago

8 0

Step 1: Simplify both sides of the equation.

4 (x−0.5)=x (3)

(4)(x)+(4)(−0.5)=x(3)(Distribute)

4x+−2=3x

4x−2=3x

Step 2: Subtract 3x from both sides.

4x−2−3x=3x−3x

x−2=0

Step 3: Add 2 to both sides.

x−2+2=0+2

Answer: x=2

german3 years ago

5 0

$4(x-0.5)=x\cdot3\\\\4x-2=3x\\\\4x-3x=2\\\\x=2$

You might be interested in

The rate of change of the downward velocity of a falling object is the acceleration of gravity (10 meters/sec 2) minus the accel

Alexus [3.1K]

Answer:

See below

Step-by-step explanation:

Write the initial value problem and the solution for the downward velocity for an object that is dropped (not thrown) from a great height.

if v(t) is the speed at time t after being dropped, v'(t) is the acceleration at time t, so the the initial value problem for the downward velocity is

v'(t) = 10 - 0.1v(t)

v(0) = 0 (since the object is dropped)

<em> The equation v'(t)+0.1v(t)=10 is an ordinary first order differential equation with an integrating factor </em>

$\bf e^{\int {0.1dt}}=e^{0.1t}$

so its general solution is

$\bf v(t)=Ce^{-0.1t}+100$

To find C, we use the initial value v(0)=0, so C=-100

and the solution of the initial value problem is

$\bf \boxed{v(t)=-100e^{-0.1t}+100}$

what is the terminal velocity?

The terminal velocity is

$\bf \lim_{t \to\infty}(-100e^{-0.1t}+100)=100\;mt/sec$

How long before the object reaches 90% of terminal velocity?

90% of terminal velocity = 90 m/sec

we look for a t such that

$\bf -100e^{-0.1t}+100=90\rightarrow -100e^{-0.1t}=-10\rightarrow e^{-0.1t}=0.1\\-0.1t=ln(0.1)\rightarrow t=\frac{ln(0.1)}{-0.1}=23.026\;sec$

How far has it fallen by that time?

The distance traveled after t seconds is given by

$\bf \int_{0}^{t}v(t)dt$

So, the distance traveled after 23.026 seconds is

$\bf \int_{0}^{23.026}(-100e^{-0.1t}+100)dt=-100\int_{0}^{23.026}e^{-0.1t}dt+100\int_{0}^{23.026}dt=\\-100(-e^{-0.1*23.026}/0.1+1/0.1)+100*23.026=1,402.6\;mt$

3 0

3 years ago

At Ralph's fruit stand X pound of grapes cost 90 cents. You want to buy 5 pounds of grapes. How

diamong [38]

Answer:At Ralph’s fruit stand ½ pound of grapes cost 90 cents. You want to buy 5 pounds of grapes.

How much will they cost?

1. What are the two possible rates for this problem?

Solution: ½ pound/90 cents 90 cents/ ½ pound

2. Show each rate as a unit rate.

Solution: . pounds of per 1 cent 180 cents per 1 pound of grapes

3. What does each unit rate tell you?

Solution: The pounds of grapes for 1 cent

The number of cents for one pound of grapes

4. Which unit rate will help you solve the problem?

Solution: 180 per 1 pound of grapes

5. If it costs 180 cents to buy 1 pound of grapes, how much will 2 pounds cost? 4 pounds?

Complete the table below.

POUNDS

GRAPES

COST IN CENTS

1 180

2 360

3 540

What pattern do you see? The cost in cents increases by 180 cents each time.

Multiply the pounds of grapes by 180 cents to get the total cost

6. Since you know the unit price, write a number sentence for the cost of five pounds of

grapes. Write an equation for the cost of any pounds of grapes.

(180 cents per pound)(5 pounds) = $9.00

(Unit rate)(pounds of grapes) = total cost

180x = y where x is the cost per pound of grapes and y is the number of pounds.

Step-by-step explanation:

8 0

3 years ago

Will give brainliest if correct

Anna71 [15]

Answer:

is this median numbers or mean?

Step-by-step explanation:

5 0

3 years ago

Mark hopes to one day earn $10,000. Estimate how<br> many clients Mark would need.

andrew11 [14]

What is his average amount of money that he earns per day so then we can solve this problem.

3 0

3 years ago

A box containing 48 pounds of coffee will be divided into packages that each hold 0.8 pound. How many packages are needed ?

Sever21 [200]

All you need to do is divide 48 (total number of pounds) by 0.8 (the amount each package holds.

Ex. 48/0.8= 60

4 0

3 years ago

Read 2 more answers