Answer:
If Hunter is right beneath Graham ( 18ft-5ft=13ft) and G's arms are 18ft above ground ( and going up, no bending) the question would be at what hight would Graham catch the ball and and how soon.
The maximum hight that the ball can reach before falling ( when the vector F - force of throwing the ball to Graham, would be equal in module to gravitational force - considering gravitational velocity of 13ft/s^2
The answer is three. i think you know where three is located in a number line
Answer:
Explanation:
The distance driven is directly proportional to the time:
Which can also be written as:
- distance₁ / time₁ = distance₂ / time₂
Here you have:
- time₁ = 1 + 2/3 hours = (3 + 2) / 3 hours = 5/3 hours
With that you can set up a proportion:
- 75 miles / (5/3) hour = x₂ / 1 hour
Solving for x₂ you get:
- x₂ = [75 miles] × 1 hour / (5/3 hour) = 3 × 75 / 5 miles = 45 miles
Answer:
B
Step-by-step explanation:
Answer:
83.34
Step-by-step explanation:
416.7 divided by 5 is equal to 83.34lbs
