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3 years ago

11

I need help.................

1 answer:

cluponka [151]3 years ago

4 0

Answer:

(1, 5)

Step-by-step explanation:

The midpoint of a line segment has coordinates that are the average of the end-point coordinates.

M = (X + Y)/2 = ((-3, 4) +(5, 6))/2 = (-3+5, 4+6)/2 = (2, 10)/2

M = (1, 5)

The midpoint is (1, 5).

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13) What is the simple interest and total amount earned on $4345 with an interest rate of

Annette [7]

Answer:

173.80 interest, 4518.80 total

Step-by-step explanation:

4345 X .03(3%)=130.35/year

130.35/12=10.8625/month

10.8625 x 16 months = 173.80 interest over 16 months

4345+173.80=4518.80 total amount

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3 years ago

Based on the attendance at past picnics, Luis expects 95% of the students in his class to attend this years picnic. If 120 stude

Sever21 [200]

Answer:

95 / 100 * 120 = 114 students

Thank you and please rate me as brainliest as it will help me to level up

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3 years ago

15 apples were equally among 5 children how many apples will each child get

Butoxors [25]

3

15 divided by 5 = 3

3 times 5 = 15

6 0

2 years ago

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Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

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3 years ago

Scott is selling baseball hats at the store he works at and makes 8% commission on anything he sells. His total sales for one da

jarptica [38.1K]

Answer:

E baboom

Step-by-step explanation:

4 0

3 years ago

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