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MAXImum [283]
3 years ago
15

Steven fill 3 pages in a stamp album. this is one sixth of the pages in the album. how many pages are there in steven stamp albu

m
Mathematics
1 answer:
Arturiano [62]3 years ago
7 0
3 pages x 6 times=18 pages
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PLEASE HELP!
Alexandra [31]

its the first one because for example [-12] and 4

the absolute value of -12 is 12 so its greater

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3 years ago
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Write a ratio for the following word phrase. Write fractions in lowest terms.42 in. to 6 ft
ollegr [7]
42 feet to 6 feet can be written as both ratio and a fraction:

42:6
42/6

If we look at the fraction, we can clearly see that we can simplify it:

42/6 = 7/1 = 7

So we can write the ratio in its lowest terms as 7:1.
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Can someone please help me!?!?!?
sineoko [7]

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3 years ago
Two-step equations - integers
Andrews [41]
Question 1. -3 + v5 = 0
Work : -3 + 5v = 0
5v = 3 ( divide )
answer v = 3/5

Question 2. 1 - 7B = -20
work : -7b = -20 - 1
-7b = -21 ( divide )
answer b = 3

question 3 : -k - 5 = 0
work : -k = 5
answer : k = - 5

Question 4 : -1 + 8a = 129
work : 8a = 129 + 1
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3 0
3 years ago
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General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}
mixer [17]

Answer:

\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

Step-by-step explanation:

Given:

\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1

First, note that

\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x

So, the equation is

-\cos x+\sin x= -1

Multiply this equation by \frac{\sqrt{2}}{2}:

-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}

The general solution is

x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

4 0
4 years ago
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