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tia_tia [17]
3 years ago
5

How would I solve this. If you answer I will give brainliest.

Mathematics
1 answer:
kobusy [5.1K]3 years ago
5 0

Answer:

∠ QPR = 64.5°

Step-by-step explanation:

The chord- chord angle QPR is half the sum of the arcs intercepted by the angle and its vertical angle, then

∠ QPR = \frac{1}{2} (QR + ST ) = \frac{1}{2} (98 + 31)° = 0.5 × 129° = 64.5°

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Lubov Fominskaja [6]

If a person invests $50 in a business and gets a percentage increase of 10%, then he would have $55 as his final payout.

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Vedmedyk [2.9K]

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A firework is launched at the rate of 10 feet per second from a point on the ground 50 feet from an observer. to 2 decimal place
Kazeer [188]

The rate of change of the angle of elevation when the firework is 40 feet above the ground is 0.12 radians/second.

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If the angle of elevation, ∠ACB = α, then

tan(α) = \frac{AB}{BC} = \frac{h}{x}

Taking inverse trigonometric function, α = tan⁻¹ (\frac{h}{x}) .............(1)

As we need to find the rate of change of the angle of elevation, so we will differentiate both sides of equation (1) with respect to time (t) :

\frac{d\alpha}{dt}=[\frac{1}{1+ \frac{h^2}{x^2}}]*(\frac{1}{x})\frac{dh}{dt}

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= 0.12 (Rounding up to two decimal places)

So, the rate of change of the angle of elevation is 0.12 radians/second.

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