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Anton [14]
4 years ago
9

Simplify the following expression:-5[(x^3 + 1)(x + 4)]​

Mathematics
1 answer:
lisov135 [29]4 years ago
8 0

Answer:

-5x^{4} -20x^{3} -5x-20

Step-by-step explanation:

-5[(x^{3} +1)(x+4)]

Use the FOIL method for the last two groups.

-5(x^{4} +4x^{3} +x+4)

Now, distribute the -5 into each term.

-5x^{4} -20x^{3} -5x-20

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3 years ago
At which value in the domain does f(x)=0 ?
lina2011 [118]

f(x)=0

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f(x)=0 , we find all the x values where y =0

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so we find all the x intercepts.

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If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

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third possible pairs = (1/2)*(15/28) = 15/56

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