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drek231 [11]
3 years ago
14

3/6 power of two + 7 × 4 − 5

Mathematics
2 answers:
prisoha [69]3 years ago
8 0

Answer:

23\frac{1}{4}

Step-by-step explanation:

(\frac{3}{6})^2+7*4-5

Use PEMDAS:

Solve the Exponent.

(\frac{a}{b})^n=\frac{a^n}{b^n}

(\frac{3}{6})^2=\frac{9}{36}=\frac{1}{4}

Multiply:

\frac{1}{4}+7*4-5\\\\\frac{1}{4}+28-5

Add and Subtract:

\frac{1}{4}+28-5\\\\28\frac{1}{4}-5\\\\ \boxed{23\frac{1}{4}}

bagirrra123 [75]3 years ago
6 0

Answer:

Your correct answer is 23 1/4.

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which of the following ordered pairs is a solution of the equation -2y + 9 = -x? A.(2,5) B.(-3,15) C.(4,-1)
vlada-n [284]

Answer:

Step-by-step explanation:

-2y + 9 = -x

x - 2y = -9

Plug in each set of points and see if the equation holds true.

A. 2 - 2(5) = ?

B. -3 - 2(15) = ?

C. 4 - 2(-1) = ?

I don't think that any of them work.

4 0
3 years ago
How do I solve the equation.×-8=4 can you help me with step by steps on this please
Sauron [17]
   This is really easy.
x-4=8 
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4 0
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The area of a rectangular lot that is 50 feet wide by 100 feet deep is:
ziro4ka [17]

The area of a rectangle can be directly calculated using the formula:

A = l * w

Where l is the length or the depth while w is the width

Therefore,

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<span>A = 5000 square feet</span>

8 0
3 years ago
The commutative property only works under what two operations?
lara [203]
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4 years ago
(\tan ^(2)\theta \cos ^(2)\theta -1)/(1+\cos (2\theta ))=
Vitek1552 [10]

(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall that

tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)

so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:

(sin²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))

Recall the double angle identity for cosine,

cos(2<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

so the 1 in the denominator also vanishes:

(sin²(<em>θ</em>) - 1) / (2 cos²(<em>θ</em>))

Recall the Pythagorean identity,

cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1

which means

sin²(<em>θ</em>) - 1 = -cos²(<em>θ</em>):

-cos²(<em>θ</em>) / (2 cos²(<em>θ</em>))

Cancel the cos²(<em>θ</em>) terms to end up with

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7 0
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