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3 years ago

Guest house is 15m long and 12m wide. what is the diagonal of the house?

Mathematics

2 answers:

Otrada [13]3 years ago

6 0

Answer:

The diagonal of the house is approximately 19.21m

Step-by-step explanation:

Taking the shape of the house as a rectangular building, if length l is 15m and width w is 12m, then to find the diagonal, we can relate the shape now formed to a right angle triangle as the diagonal line divides the rectangular house into 2 right angled triangle.

We can now say the diagonal line is d.

To solve the question, we can consider pythagoras theorem which is

$a^{2}$ + $b^{2}$ = $c^{2}$

The length l and width w can be taking as opposite and adjacent a and b respectively, while diagonal d can be taking as hypothenus c

$l^{2}$ + $w^{2}$ = $d^{2}$

Substitute for length 15m and width 12m, we will have

$15^{2}$ + $12^{2}$ = $d^{2}$

225 + 144 = $d^{2}$

369 = $d^{2}$

d = $\sqrt{369}$

d = 19.2094

d ≈ 19.21m

Ann [662]3 years ago

4 0

I think I got the answer. Use at your own risk. But I think the answer is 19.21

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Find the surface area of the solid. Round to two decimal places

Ne4ueva [31]

Check the picture below.

so, to get the area of the triangles, we can simply run a perpendicular line from the top to the base, and end up with a right-triangle with a base of 22 and a hypotenuse of 34, let's find the altitude.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{34^2-22^2}=b\implies \sqrt{672}=b$

so then the surface area of the triangular prism is,

$\bf \stackrel{\textit{left and right}}{2(34\cdot 76)}~~+~~\stackrel{\textit{bottom}}{(44\cdot 76)}~~+~~\stackrel{\textit{front and back}}{2\left[\cfrac{1}{2}(44)(\sqrt{672}) \right]}
\\\\\\
8512~~+~~(44)(\sqrt{672})\qquad \approx\qquad 9652.61036291978$

5 0

3 years ago

An ice cream store has the pricing shown below. You want to determine the best value. The height of the cone is 4.5 in and the d

nignag [31]

Solution:

Step 1:

We will calculate the volume of ice cream in the single scoop

The volume of the ice cream will be

$\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{2}{3}\pi r^3 \\ r=\frac{2in}{2}=1in(cone) \\ h=4.5in \\ r=\frac{3in}{2}=1.5in(radius\text{ of the hemisphere\rparen} \end{gathered}$

By substituting the values, we will have

$\begin{gathered} V=\frac{1}{3}\pi r^{2}h+\frac{2}{3}\pi r^{3} \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5+\frac{2}{3}\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{99}{14} \\ V=\frac{165}{14} \\ V=11.79in^3 \end{gathered}$

Step 2:

We will use the formula below to calculate the volume of the two scoops of ic cream

$\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{4}{3}\pi r^3 \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5in+\frac{4}{3}\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{99}{7} \\ V=\frac{132}{7} \\ V=18.86in^3 \end{gathered}$

Step 3:

We will use the formula below to calculate the volume of the three scoops of ic cream

$\begin{gathered} V=\frac{1}{3}\pi r^2h+\frac{6}{3}\pi r^3 \\ V=\frac{1}{3}\times\frac{22}{7}\times1^2\times4.5+2\times\frac{22}{7}\times1.5^3 \\ V=\frac{33}{7}+\frac{297}{14} \\ V=\frac{363}{14} \\ V=25.93in^3 \end{gathered}$

For the first ice cream with one scoop