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Molodets [167]
3 years ago
14

Guest house is 15m long and 12m wide. what is the diagonal of the house?

Mathematics
2 answers:
Otrada [13]3 years ago
6 0

Answer:

The diagonal of the house is approximately 19.21m

Step-by-step explanation:

Taking the shape of the house as a rectangular building, if length l is 15m and width w is 12m, then to find the diagonal, we can relate the shape now formed to a right angle triangle as the diagonal line divides the rectangular house into 2 right angled triangle.

We can now say the diagonal line is d.

To solve the question, we can consider pythagoras theorem which is

a^{2} + b^{2} = c^{2}

The length l and width w can be taking as opposite and adjacent a and b respectively, while diagonal d can be taking as hypothenus c

l^{2} + w^{2} = d^{2}

Substitute for length 15m and width 12m, we will have

15^{2} + 12^{2} = d^{2}

225 + 144 = d^{2}

369 =  d^{2}

d = \sqrt{369}

d = 19.2094

d ≈ 19.21m

Ann [662]3 years ago
4 0
I think I got the answer. Use at your own risk. But I think the answer is 19.21
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Mars2501 [29]

Answer:

Point O is the center of the circle.

<u>Part (a)</u>

\overline{A\:\!F} is a chord.

\overline{OD} is a segment of the radius and is perpendicular to  \overline{A\:\!F}

If a radius is perpendicular to a chord, it bisects the chord (divides the chord into two equal parts).

Therefore, \overline{AD}=\overline{DF}

<u>Part (b)</u>

If \overline{BE} was extended past point E to touch the circumference it would be a chord.

As \overline{OC} is perpendicular to \overline{BE},  it would bisect the chord, but as \overline{BE} is only a portion of a chord, \overline{OC} <u>does not</u> bisect \overline{BE}.

Therefore, there is no length equal to \overline{BC}.

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2 years ago
Write a number sentence that<br> equals 4/6​
Arturiano [62]

when you have a function that is 4/6 think of it as reversed the number its going to be 4/6=6×4.

7 0
3 years ago
Help me pleasee i need help this is my final btw
Molodets [167]

Answer:

12 sq units

Step-by-step explanation:

height = 3

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5 0
2 years ago
Evaluate the definite integral. 1/4 csc(2πt) cot(2πt) dt 1/12
Afina-wow [57]
Hey there, hope I can help!

\frac{1}{4}\csc \left(2\pi t\right)\cot \left(2\pi t\right)dt\frac{1}{12}

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\mathrm{Apply\:rule}\:1\cdot \:a=a \ \textgreater \  \frac{dt}{4\cdot \:12}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:12=48 \ \textgreater \  \frac{dt}{48}\csc \left(2\pi t\right)\cot \left(2\pi t\right)

\mathrm{Multiply\:fractions}: \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{dt\csc \left(2\pi t\right)\cot \left(2\pi t\right)}{48}

Hope this helps!
5 0
3 years ago
P is the set of natural numbers<br> less than 6.
Wewaii [24]

Answer:

Therefore,

P = { 1 , 2 , 3 , 4 , 5 }

Step-by-step explanation:

Natural numbers:

Natural numbers are those numbers starting from 1 , 2 , 3 , 4 ,......... and so on.

Also it is denoted by 'N'.

Zero does not include a natural number.

Therefore the set of natural numbers less than 6 is 1 , 2 , 3 , 4 , and 5.

Here in the question it is given that

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less than 6.

∴ P = { 1 , 2 , 3 , 4 , 5 }

6 0
3 years ago
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