How can I solve this ?

Mathematics

2 answers:

PIT_PIT [208]3 years ago

7 0

Answer:

you start by seeing how many times 8 goes into (7) which is zero Then you add the (8).

how many times does 8 go into 78 = 9 with 6 left over.

you bring the 6 down and the next 8 giving you (68) = 8 with 4 left over

so you bring the 4 and the two down giving you (42) = 5 with 2 left over.

so your answer is 985 remainder 2

Step-by-step explanation:

LuckyWell [14K]3 years ago

3 0

Answer:

985.25

Step-by-step explanation:

An easy way to divide by larger numbers is to see if the divisor fits into the thousands, hundreds, tens, and ones place.

8 doesn't go into 7, so you'd bring down the number in the hundreds place and so on and so forth.

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Step-by-step explanation:

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Take these examples:

$\sqrt{9-4} =\sqrt{5} \\\sqrt{9}-\sqrt{4}=3-2=1\\ $Clearly \sqrt{5}\neq 1\\$Similarly\\\sqrt{9+4} =\sqrt{13} \\\sqrt{9}+\sqrt{4}=3+2=5\\ $Clearly \sqrt{13}\neq 5\\$