Answer:
D it
Step-by-step explanation:
We have two equations, A quadratic and a linear equation.
The domain of a linear equation and quadratic equation is all real numbers but since it dealing with time we must make sure the roots or x-intercepts is positive.
Looking at the quadratic equation, we can use the discramnt formula to see if all roots are positve.
The discramnt is greater than zero so there is two distinct real roots. So let check if they are positve
If you graph the equation, it intercepts at two positve roots so it is D
Part A
Represents 'Reflection'. This is so because the y-coordinates of P, Q and R remain the same in P' , Q' and R', and only the x-coordinate changes. Hence, it is reflection along the y-axis
Part B
Represents 'Rotation'. Here, the x-coordinates and y-coordinates of each of the points have changed, and the figure has been rotated clockwise around the point Q by 90°
Part C
Represents a combination of 'Translation' and 'Reflection'. Here either of the two has happened:
- First, all the points have been moved downwards by a fixed distance, thus changing the y-coordinate. Then, the resulting image has been reflected along the y-axis, thus changing the x-coordinate of all the points
- First, all the points have been moved to the right by a fixed distance, thus changing the x-coordinate. Then, the resulting image has been reflected along the x-axis, thus changing the y-coordinate of all the points
Part D
Represents 2 'Translations'. Here the image has been shifted by a fixed distance in both the downward direction and the right direction. Thus, it has resulted in change of both x and y coordinates.
Answer:
$14,644.63
Step-by-step explanation:
To solve this problem we can use the compound interest formula which is shown below:
<em>P = initial balance
</em>
<em>r = interest rate
</em>
<em>n = number of times compounded annually
</em>
<em>t = time
</em>
<em />
First change 12% into a decimal:
12% -> 
-> 0.12
Lets plug in the values:
Tammy will own $14,644.63 after 8 years,
Answer:
Well, you could always just put it onto a scale to find the mass. But assuming you aren't talking about a laboratory setting. sorry if its all werid i cant really put it into how it supposed to be
The general formula is:
ρ
=
m
V
where
ρ
is density in
g/mL
if mass
m
is in
g
and volume
V
is in
mL
.
So to get the mass...
m
=
ρ
V
Or to get the volume...
V
=
m
ρ
When you have the volume and not the density, and you want to find mass, you will need to find the density yourself. It's often readily available on the internet.
Just replace "[...]" with the object you want, and if it's not exactly what you need, consider it an estimate.
These days, you should be able to search for the density of any common object.
When you have the density and volume but not the mass, then just make up a mass.
You shouldn't need specific numbers to do a problem. You can always solve a problem in general and get a solution formula. If you need to, just make up some numbers that you know how to use.
