Answer:
1) The square ABCD was dilated to form square A'B'C'D' using a scale factor of 1/2
2) The pair of polygons is not similar because their corresponding sides are not proportionals.
Step-by-step explanation:
1) Scale factor: f=?
f=Final dimension / Initial dimension
f=A'B'/AB=B'C'/BC=C'D'/CD=A'D'/AD
f=2/4
Simplifying the fraction dividing the numerator and denominator by 2:
f= (2/2) / (4/2)
f=1/2
2) Let's check the proportion between their corresponding sides:
AM/A'M'=(11 ft)/(9.4 ft)=1.17
HT/H'T'=(11 ft)/(9.4 ft)=1.17
HM/H'M'=(10 ft)/(8.4 ft)=1.19
AT/A'T'=(10 ft)/(8.4 ft)=1.19
AM/A'M'=HT/H'T'=1.17 but different to 1.19=HM/H'M'=AT/A'T'
Then, the pair of polygons is not similar
Time will usually go on the x-axis.
It is true. Hope it help!
Let children be x
Adult be y
5.10x+9.40y=1184.20 ... 1
x+y=158 ... 2
From 1// 510x+940y=118420 ... 3
From 2// y=158-x ... 4
Sub 4 into 3
510x+940(158-x)= 118420
510x+148520-940x=118420
-430x= -30100
x=70
As we know that children are x, 70 children tickets were sold.
To make all the values integers, that means we need to remove any fractions. The x variable is multiplied by "-3/4." To make it an integer, multiply both sides of the equation by 4. Therefore,
4y = -3x + 12
To check your work, you can divide both sides by 4 and see that -3x/4 = (-3/4)x and 12/4 = 3.
