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FromTheMoon [43]
3 years ago
14

PLEASE HELP ME WITH THIS IF U ARE GOOD @ MATH ! WILL MARK 5 STARS THANKS AND BRAINLEST !!!!!!

Mathematics
2 answers:
Nady [450]3 years ago
5 0
The scale factor used was 1/2. It is a reduction because the prime figure is smaller.

The polygons are not similar because the ratio of their corresponding sides are not the same and do not simplify to be the same either.
lys-0071 [83]3 years ago
4 0

Answer:

1) The square ABCD was dilated to form square A'B'C'D' using a scale factor of 1/2

2) The pair of polygons is not similar because their corresponding sides are not proportionals.

Step-by-step explanation:

1) Scale factor: f=?

f=Final dimension / Initial dimension

f=A'B'/AB=B'C'/BC=C'D'/CD=A'D'/AD

f=2/4

Simplifying the fraction dividing the numerator and denominator by 2:

f= (2/2) / (4/2)

f=1/2


2) Let's check the proportion between their corresponding sides:

AM/A'M'=(11 ft)/(9.4 ft)=1.17

HT/H'T'=(11 ft)/(9.4 ft)=1.17

HM/H'M'=(10 ft)/(8.4 ft)=1.19

AT/A'T'=(10 ft)/(8.4 ft)=1.19

AM/A'M'=HT/H'T'=1.17 but different to 1.19=HM/H'M'=AT/A'T'

Then, the pair of polygons is not similar

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