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SCORPION-xisa [38]

4 years ago

14

A small school employs 5 teachers who make between $40,000 and $70,000 per year The newest teacher, Valerie, decides to teach pa

rt-time which decreases her salary from $40,000 to $20,000 per year. The rest of the salaries stay the same How will decreasing Valerie's salary affect the mean and median?

2 answers:

Nezavi [6.7K]4 years ago

7 0

Yes it will slightly but not much

m_a_m_a [10]4 years ago

7 0

Answer:

Step-by-step explanation:

No of teachers in the school = 5

Salaries they make =40000 to 70000

When one of the five teachers reduce salary to 20000/- per year, median may or may not shift one number to the left

Mean will definitely decrease by difference/5 = 4000 dollars

Thus mean will defintely change by reduction of 4000 dollars.

Median has a chance to remain the same or may shift left side one item.

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at what rate of compound interest per annum will the compound interest on rupees 270000 be rupees 8937 in 3 years

KiRa [710]

Answer:

if you have 270000

Step-by-step explanation:

if you spend money 261063 in 3 years

270000-261063

8937

7 0

3 years ago

0.6x 4.8=7.2 without integers

velikii [3]

2.88x=7.2
x=7.2/2.88
x=2.5

5 0

3 years ago

Find how many positive integers with exactly four decimal digits, that is, positive integers between 1000 and 9999 inclusive, ha

zmey [24]

Answer:

(a) There are 257 numbers which are divisible by 5 and by 7

(b) There are 1286 numbers which are divisible by 7

(c) There are 4500 even numbers

(d) There are 514 numbers which are divisible by 5 but not by 7

Step-by-step explanation:

(a) Since, LCM(5, 7) = 35,

Thus, the numbers divisible by 5 and by 7 between 1000 and 9999,

1015, 1050, 1085............, 9975

Which is an AP,

Having first term, a = 1015,

Common difference, d = 35,

Last term, l = 9975

If n be the number of terms,

$\because l = a + (n-1)d$

$9975 = 1015 + (n-1)35$

$9975 - 1015 = (n-1)35$

$8960 = (n-1)35$

$256 = n-1$

$\implies n = 256 + 1 = 257$

(b) Similarly, number divisible by 7,

1001, 1008, 1015............, 9996

Here, a = 1001, d = 7, l = 9996

$9996 = 1001 + (n-1)7$

$9996 - 1001 = (n-1)7$

$8995 = (n-1)7$

$1285 = n-1$

$\implies n = 1285 + 1 = 1286$

(c) Even numbers between 1000 and 9999 inclusive

1000, 1002, 1004, 1006,........9998

Here, a = 1000, d = 2, l = 9998

$9998 = 1000 + (n-1)2$

$9998 - 1000 = (n-1)2$

$8998 = (n-1)2$

$4499 = n-1$

$\implies n = 4499 + 1 = 4500$

(d) Number divisible by 5,

1000, 1005, 1010............, 9995

Here, a = 1000, d = 5, l = 9995

$9995 = 1000 + (n-1)5$

$9995 - 1000 = (n-1)5$

$8995 = (n-1)5$

$1799 = n-1$

$\implies n = 1799 + 1 = 1800$

Hence, the number divisible by 5 but not by 7 = numbers divisible by 5 - number divisible by 7

= 1800 - 1286

= 514

8 0

4 years ago

Can someone help me find the value of A, B, and C

Kamila [148]

A= 72 1/2 the arc when connected to the edge of the circle
B= 24 1/2 the arc when connected to the edge of the circle
C= 84 72+24=96 180-96= 84 and vertical angles are congruent

3 0

3 years ago

What percent of 150 is 96?

lara31 [8.8K]

The first one:
96 ÷ 150
<span>0.64 </span>
<span>0.64 * 100
64%
</span>
Second one:
225% × 3.6
2.25 ×<span> 3.6 </span>
8.1

Third one:
63 ÷ 135
<span>63 </span>÷<span> 1.35 </span>
46.67

Fourth one:
0.105 ÷ 3.5
<span>0.105 </span>÷<span> 0.035 </span>
<span>3</span>

5 0

4 years ago

Read 2 more answers