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alisha [4.7K]
3 years ago
14

Subtract: x^2+4xy −3y^2 from 2x^2−5xy+y^2

Mathematics
2 answers:
slavikrds [6]3 years ago
8 0

2x^2−5xy+y^2 - (x^2+4xy −3y^2)

= 2x^2−5xy + y^2 - x^2 - 4xy + 3y^2

= x^2 - 9xy + 4y^2


answer

x^2 - 9xy + 4y^2

Zina [86]3 years ago
8 0

if you combine your like terms you would get -xy-x^2-2y^2. hope that helps!

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To solve a triangle means to obtain al the missing parts of the triangle.

<h3>How do you solve a triangle?</h3>

To solve a triangle means to obtain al the missing parts of the triangle. Now we have the following information;

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b^2 = a^2 + c^2 - 2acCos B

b^2 = (11)^2 + (8)^2 - [2 * 11 * 8 * cos 51]

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7 0
2 years ago
WILL MARK BR HELP ME PLZ FAST AS POSSIBLE
posledela
<h2>Answer:</h2>

<h2>cos theta= adjacent side/ hypotenuse</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8√5+1/4 = x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenuse </h2>

cos 36= x/8√5+1/4 = x/8

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Read 2 more answers
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