Answer:
The time taken by the car to get to the other side of an intersection is, t = 4.9 s
Explanation:
Given data,
The acceleration of the car, a = 2.5 m/s²
The initial velocity of the car, u = 0
The distance traveled, s = 30 m
Using the II equations of motion,
<em> S = ut + ½ at²</em>
Therefore,
t = √(2S/a) ( since u = 0)
Substituting the values
t = √(2 x 30 / 2.5)
= 4.9 s
Hence, the time taken by the car to get to the other side of an intersection is, t = 4.9 s
Work done is given by product of force and displacement due to that force
So here we will have
here we know that
Now work done is given as
so it will do 16 J work to move the box
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Useful output = (efficiency) x (input energy)
(1000 J) = (0.12) x (input energy)
Divide each side
by 0.12 : 1,000 J / 0.12 = input energy
Input energy = (8,333 and 1/3) J