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JulsSmile [24]
3 years ago
8

A balance accurate to one-hundredth of a gram measures the mass of a rock to be 56.10 grams. How many significant digits are in

this value?
Physics
2 answers:
natita [175]3 years ago
7 0

By definition we have to:

The significant figures are the digits of a number that we consider not null.

We have different rules to consider significant figures depending on the number given.

Among some of the rules are:

1) All non-zero digits are significant.

2) For numbers greater than 1, the zeros to the right of the comma are significant.

For this case we have the following number:

56.10 grams

According to the rules, the number zero is counted as a significant figure.

Therefore, the number has four significant figures.

Answer:

56.10 grams = four significant figures.

natali 33 [55]3 years ago
3 0
There are 3 significant didgits
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SHOW WORK
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Answer:

Follows are the solution to the given question:

Explanation:

For point a:

T= 2\pi \sqrt{\frac{m}{k}}\\\\k = \frac{4 \pi^2 m}{T^2}\\\\= \frac{4 \times (3.14)^2 \times 3}{2^2}\\\\=29.578 \ \frac{N}{m}\\\\

For Point b:

E=\frac{1}{2} m a^2 w^2\\\\

   =\frac{1}{2} \times m \times a^2 \times \frac{4\pi^2}{T^2}\\\\=\frac{1}{2} \times 3 \times (0.15)^2 \times \frac{4\times 3.14^2}{2^2}\\\\=0.332 \ J

For Point C:

V_{max}= a w

        = (0.15) \times \frac{2\pi}{T}\\\\= (0.15) \times \frac{2\times 3.14}{2}\\\\=0.471 \frac{m}{s}

For point D:

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