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JulsSmile [24]
3 years ago
8

A balance accurate to one-hundredth of a gram measures the mass of a rock to be 56.10 grams. How many significant digits are in

this value?
Physics
2 answers:
natita [175]3 years ago
7 0

By definition we have to:

The significant figures are the digits of a number that we consider not null.

We have different rules to consider significant figures depending on the number given.

Among some of the rules are:

1) All non-zero digits are significant.

2) For numbers greater than 1, the zeros to the right of the comma are significant.

For this case we have the following number:

56.10 grams

According to the rules, the number zero is counted as a significant figure.

Therefore, the number has four significant figures.

Answer:

56.10 grams = four significant figures.

natali 33 [55]3 years ago
3 0
There are 3 significant didgits
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Answer:

A

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6 0
3 years ago
A student sects a leaf of length 7.2 cm to draw. Her drawing is 28.8 cm in length. What is the magnification of the drawing?
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Answer:

A) x4

Explanation:

Magnification is equal to image size divided by the actual size, or M = I/A.

The image size is the student's drawing, which is 28.8 cm, and the actual size is 7.2 cm. Divide them, and cancel out the units, and you should get:

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7 0
3 years ago
A rectangular loop with dimensions 4.20 cm by 9.50 cm carries current I. The current in the loop produces a magnetic field at th
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Answer:

I=1.48 A

Explanation:

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B=3.1 x 10⁻5 T

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B=\dfrac{2\mu _oI}{\pi}D

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D=\dfrac{\sqrt{l^2+b^2}}{lb}

By putting the values

D=\dfrac{\sqrt{l^2+b^2}}{lb}

D=\dfrac{\sqrt{0.042^2+0.095^2}}{0.042\times 0.095}

D=26.03 m⁻¹

B=\dfrac{2\mu _oI}{\pi}D

3.1\times 10^{-5}=\dfrac{2\times 4\times \pi \times 10^{-7} I}{\pi}\times 26.03

I=\dfrac{3.1\times 10^{-5}}{{2\times 4\times 10^{-7} }\times 26.03}

I=1.48 A

8 0
3 years ago
How can people reconcile technology with environmental preservation?​
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2. Saving endangered wildlife

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3. Adopting a smarter lifestyle

- smart homes that promote energy saving and green - living .
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Hope this helps :)
5 0
3 years ago
g We saw in class that in a pendulum the string does no work. We also saw that the normal force does no work on an object slidin
Ymorist [56]

Answer:

From question (a) and (b) the pendulum motion is perpendicular to the force so the normal force will do no work and the tension in the string of the pendulum will not work

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c

An example will be a where a stone is attached to the end of a string and is made to move in a circular motion while keeping the other end of the string in a fixed position        

d

A dog walking along a surface which has friction, here the frictional force would acting in the direction of the motion and this would do positive work  

Explanation:

5 0
3 years ago
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