That's actually a trick question. There would be no work done on the weights because the weight lifter is holding it with no net force change. Also, the formula for work is W=Fd. There is no Δx distance in this instance. I hope this helps! Have a good day.
Answer: 13.46 m/s
Explanation:
Initial velocity V1 = 5.82 m/s
acceleration A = 2.35m/s^2
Time taken T = 3.25s
Final velocity V2 = ?
Recall that acceleration is the rate of change of velocity per unit time i.e acceleration = (V2 - V1)/T
2.35m/s^2 = (V2 - 5.82 m/s) / 3.25s
cross multiply
2.35m/s^2 x 3.25s = (V2 - 5.82 m/s)
7.6375m/s = V2 - 5.82 m/s
V2 = 7.6375m/s + 5.82m/s
V2 = 13.46 m/s
Thus, the car final velocity is 13.46 m/s
Answer:
x = vt
Explanation:
At constant speed, distance = speed × time.
x = vt
To solve for time:
t = x / v
This equation works because at constant speed, there is no acceleration.
Δx = v₀ t + ½ at²
Δx = v₀ t + ½ (0) t²
Δx = v₀ t
Answer: gravitational force between them will be reduced by one - fourth ( 1/4) of its initial value.
Explanation: Gravitational force between two bodies obeys inverse square law. That is, gravitational force between two bodies is inversely proportional to the square of the distance between the two bodies.
When the mammoth is at a distance that is twice the original distance, the gravitational force between them will be reduced by one - fourth ( 1/4 ) of its initial value.
Answer:
Explanation:
Newton's law states that F=mg, or in other applications F=ma, where:
F= force acting on the system
m= mass of the system and
a= acceleration (or g= gravitational acceleration which is 9.8m/s^2)
In your question we know the following variables:
The mass of the arrow (m= 100g, however we should use kilograms- 0.1kg)
The acceleration of the arrow (a=50m/s^2)
If we substitute these values into our given equation, we can find the force acting on the arrow.
F = m x a
F= (0.1) x (50)
F = 5N
hope this helps :)