Answer:
1. a) Draw a line towards the right side from the engine
b) This force pushes the boat forward and helps it accelerate further
2. a) Fixed volume for both solid and liquid
Compressible for only solid
Fixed shape is also for only Solid
b) The answer is 'c'
c) Solids, because they have their particles closely packed therefore they can be compressed (not so sure bout this answer)
In a quarter of an hour it will travel 1/4 x 90 = 22.5Km
The time difference between their landing is 2.04 seconds.
<h3>
Time of difference of the two balls</h3>
The ball thrown vertical upwards will take double of the time taken by the ball thrown vertically downwards.
Time difference, = 2t - t = t
t = √(2h/g)
where;
- h is the height of fall
- g is acceleration due to gravity
Apply the principle of conservation of energy;
¹/₂mv² = mgh
h = v²/2g
where;
h = (20²)/(2 x 9.8)
h = 20.41 m
<h3>Time of motion</h3>
t = √(2 x 20.41 / 9.8)
t = 2.04 s
Thus, the time difference between their landing is 2.04 seconds.
Learn more about time of motion here: brainly.com/question/2364404
#SPJ1
Answer:
3.21
Explanation:
The relation between frequency and wavelength is shown below as:
c is the speed of light having value
Given, Frequency = 93.5 MHz =
Thus, Wavelength is:
<u>Answer - A.</u>
Complete question is;
Does the galvanometer deflect to the left or the right when
a) the magnet is being pushed in
b) the magnet is being pulled out
c) the magnet is being held steady?
Answer:
Option A - when the magnet is being pulled out
Explanation:
Faraday’s law of electromagnetic induction states that: “Voltage is induced in a circuit whenever relative motion exists between the conductor and the magnetic field, and the magnitude of the voltage will be proportional to the rate of change of the flux”.
Now, applying it to the question, When the magnet is moved towards the sensitive center of the galvanometer and then pulled out, the needle of the galvanometer will deflect away from its center position in one direction only but when it is held steady, the needle of the galvanometer will return back to zero.