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Solve. –4t ≤ 48 A. t ≥ –12 B. t ≤ –12 C. t ≥ 12 D. t ≤ 12

Oksana_A [137]

$-4t \leq 48 \ \ \ : |(-4) \\ \\ t \geq 12$

<em>\\\ Ben</em>

3 0

3 years ago

Choose at least three different careers you are interested in pursuing. Research the education level the career requires, the an

AveGali [126]

Answer:

The career planning process is ongoing and sequential. Since it is fluid rather than chronological, you move to the next step only when you are ready to do so, and you may move back and forth between steps at any given time. The career planning process is also cyclic. When career change is desired anytime during your work life, you may repeat the process once again. Data from the U.S. Bureau of Labor Statistics indicates that the majority of members of the labor force will make three to four major changes in their career during their 35 to 45 years of working. Because human beings are complex, each of us has unique aspirations, goals, potential for development, and limitations. Although we can follow the same process, career planning outcomes must be individualized.

Step-by-step explanation:

5 0

3 years ago

You have been asked to cut a 1.5m roll of bubble wrap into 30 cm lengths, which are used to wrap CDs before posting to clients.

dlinn [17]

Answer:

c. 5

Step-by-step explanation:

1.5m = 1.5*100 cm = 150 cm

Divide 150 cm by 30 cm,

150/30 = 5

8 0

2 years ago

A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a

sdas [7]

Answer:

$y=-\dfrac{13}{49}x^2$

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

$y=ax^2+bx+c$

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

$-13=a(-7)^2+b(-7)+c$

$49a-7b+c=-13$

(x,y) = (7,-13)

$-13=a(7)^2+b(7)+c$

$49a+7b+c=-13$

(x,y) = (0,0)

$0=a(0)^2+b(7)+c$

$c=0$

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

$49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13$

$49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13$

we can solve these two equation using the elimination method, by simply adding the two equations

$\quad\quad49a-7b=-13\\+\quad49a+7b=-13$

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$\quad\quad 98a=-26$

$\quad\quad a=-\dfrac{13}{49}$

Now we can plug this value of a in any of the two equations.

$49a-7b=-13$

$49\left(-\dfrac{13}{49}\right)-7b=-13$

$-13-7b=-13$

$-7b=0$

$b=0$

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

$y=\left(-\dfrac{13}{49}\right)x^2+0x+0$

$y=-\dfrac{13}{49}x^2$

$49y=-13x^2$

This our equation of the arch!

5 0

3 years ago

Please anyone answer me

ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

$A\frac{}{1} = ∫g(x)dx = ∫xdx = \frac{1}{2} {x}^{2} | \frac{2}{0} = 2$