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Vesnalui [34]
3 years ago
6

3, 6, 4, 8, 6, 12 what are the next three numbers in this pattern

Mathematics
2 answers:
vlabodo [156]3 years ago
8 0
10, 20, and 18.

The pattern is x2 -2, so that's how you get those.
FrozenT [24]3 years ago
5 0
The next three numbers are these ---> 10, 20, 18
3, 6, 4, 8, 6, 12, 10 , 20, 18

~Hope this helped!
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in abbys grade, there 70 students. currently, 10% of them are enrolled in health. how many students are enrolled in health?​
goblinko [34]

Answer:

7 students.

Step-by-step explanation:

10% of 70 is 7.

4 0
3 years ago
What is the greatest common factor of 12 and 16
Assoli18 [71]

Answer:

4

Step-by-step explanation:

12 can be dived into 4 a total of 3 times. 16 can be divided into 4 a total of 4 times

5 0
3 years ago
What is 2/5 divided by 4/3
Andrej [43]

Answer:

0.5333

Step-by-step explanation:

\frac{2}{5}  \div  \frac{4}{3}  \\   \\  \frac{2 \times 4}{5\times 3}  =  \frac{8}{15} \\   \\  \frac{8}{15}  = 0.5333

Please mark 2 brainliests because I need.

3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
astra-53 [7]

\sqrt{5}
5 0
3 years ago
Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0
eduard
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2787701

_______________


\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}


Square both sides:

\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}

\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}


Since \mathsf{sin\,\theta} is positive, you can discard the negative sign. So,

\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}


Substitute this value back into \mathsf{(i)} to find \mathsf{cos\,\theta:}

\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}


I hope this helps. =)


Tags:   <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>

7 0
3 years ago
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