Answer:
92.9997<
<99.5203
Step-by-step explanation:
Using the formula for calculating the confidence interval expressed as:
CI = xbar ± Z * S/√n where;
xbar is the sample mean
Z is the z-score at 90% confidence interval
S is the sample standard deviation
n is the sample size
Given parameters
xbar = 96.52
Z at 90% CI = 1.645
S = 10.70.
n = 25
Required
90% confidence interval for the population mean using the sample data.
Substituting the given parameters into the formula, we will have;
CI = 96.52 ± (1.645 * 10.70/√25)
CI = 96.52 ± (1.645 * 10.70/5)
CI = 96.52 ± (1.645 * 2.14)
CI = 96.52 ± (3.5203)
CI = (96.52-3.5203, 96.52+3.5203)
CI = (92.9997, 99.5203)
<em>Hence a 90% confidence interval for the population mean using this sample data is 92.9997<</em><em><99.5203</em>
Answer:
x^2+4x-32=0
(mid-term breaking---4 x 8=32)
x^2+8x-4x-32=0
x(x+8)-4(x+8)
x+8=0 or x-4=0
So x=+4 or x=-8
Step-by-step explanation:
Step-by-step explanation:
We just subsitue 3 for x and -4 for y, so we get
So
Answer:
The inequality that can be used to determine how many rides r and games g Tyler can pay for at the carnival is:
0.75r+0.50g≤20, where:
r is the number of rides
g is the number of games
Step-by-step explanation:
With the information provided, you can say that the amount spent at the carnival is equal to the cost per ride for the number of rides plus the cost per game for the number of games. Also, given that the statement indicates that Tyler has at most $20, the inequality would indicate that the amount spent has to be less than or equal to 20. According to this, the inequality that can be used to determine how many rides r and games g Tyler can pay for at the carnival is:
0.75r+0.50g≤20, where:
r is the number of rides
g is the number of games
1.7=2
8.1=8
6.9=7
4.3=4
Hope this helps
