Given:
10 cousins
1 Jackson cousin
twice as many Lopez cousin as Chen cousin.
The unknown are the number of Lopez cousin and Chen cousin.
Let x represent the number of Chen cousin. Since Lopez cousin is twice the number of Chen cousin, the Lopez cousin is represented by 2x.
1 + 2x + x = 10
3x = 10 - 1
3x = 9
x = 9/3
x = 3 → Number of Chen cousins
2x → 2(3) = 6 → Number of Lopez cousins
There is 1 Jackson cousin, 6 Lopez cousins, and 3 Chen cousins. For a total of 10 cousins.
If 10t = 9
t = 9/10 (as a fraction)
This is equivalent to 0.9
New answer is -0.9. step by step in the comments
